In any triangle, medians meet at a point and divide each other as the ratio of $2:3$
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In any triangle, medians meet at a point and divide each other as the ratio of $2:3$
If $AD$ and $PM$ are medians of triangles $ABC$ and $PQR$, respectivetly where $\triangle ABC \sim \triangle PQR$, then $\dfrac {AB}{PR}=\dfrac {AC}{PM}$.