Tag: basic proportionality theorem and its converse

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Multiple choice maths triangles relation between perimeters of similar shapes basic proportionality theorem and its converse basic proportionality theorem

If $AD$ and $PM$ are medians of triangles $ABC$ and $PQR$, respectivetly where $\triangle ABC \sim \triangle PQR$, then  $\dfrac {AB}{PR}=\dfrac {AC}{PM}$.

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For similar triangles, the ratio of corresponding medians is equal to the ratio of corresponding sides (AB/PQ = AD/PM). The provided ratio AB/PR = AC/PM is not a standard property of similar triangles.