Tag: the s-block elements

Questions Related to the s-block elements

$30\ g$ of Magnesium and $30\ g$ of oxygen are reacted, then the residual mixture contains:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. $50\ g$ of Magnesium oxide and $10\ g$ of oxygen

  2. $40\ g$ of Magnesium oxide and $20\ g$ of oxygen

  3. $45\ g$ of Magnesium oxide and $15\ g$ of oxygen

  4. $50\ g$ of Magnesium only

Show answer
Correct Option: A
Explanation:
$2Mg+ { O } _{ 2 } \rightarrow 2 MgO$
According to the above reaction,
$28.6 g (2 mole)\ Mg$ combine with $32 g (1mole)$ of ${ O } _{ 2 }$ to give $80.6g(2mole)$ of MgO.
thus,
$30 g\ Mg$ will combine with $20 g$ of ${ O } _{ 2 }$ to produce $50 g\ MgO$ and $10 g$ ${ O } _{ 2 }$will remain unreactive.

About $2.5\%$ gypsum $(CaSO _{4}.H _{2}O)$ is also added to cement as one of the consituents its function is to:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. Slow down the setting process to increase strength

  2. Speed the setting process to increase strength

  3. Absord moisture

  4. Make it anti-rusting

Show answer
Correct Option: A
Explanation:

Gypsum is a mineral and is hydrated calcium sulphate in chemical form. Gypsum plays a very important role in controlling the rate of hardening of the cement. During the cement manufacturing process, upon the cooling of clinker, a small amount of gypsum is introduced during the final grinding process.Gypsum is added to control the “setting of cement”. If not added, the cement will set immediately after mixing of water leaving no time for concrete placing.
conclusion: hence the option (A) is correct

A metal $M$ readily forms its sulphate $MSO _{4}$ which is water soluble. It forms its oxide $MO$ which becomes inert on heating. It forms an insoluble hydroxide $M(OH) _{2}$ which is soluble in $NaOH$ solution. Then M is:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. $Mg$

  2. $Ba$

  3. $Ca$

  4. $Be$

Show answer
Correct Option: D
Explanation:

In the periodic table, on moving down, water solubility of alkaline earth metal decreases. Oxides and hydroxides of alkaline earth metal are basic except Be which is amphoteric.
Hence the metal M is Be.
conclusion: hence the option (D) is correct.

Several blocks of magnesium are fixed to the bottom of a ship to:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. make the ship lighter

  2. prevent action of water and salt

  3. prevent puncturing by under-sea rocks

  4. keep away the sharks

Show answer
Correct Option: A
Explanation:

Several blocks of magnesium are fixed to the bottom of a ship to. Magnesium, on account of its lightness, great affinity for oxygen and toughness is used in ship. Being a lighter element, magnesium makes the ship lighter when it is fixed to the bottom of the ship.

Hence option A is correct answer.

Gypsum is not chemically similar to:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. Selenite

  2. Alabaster

  3. Anhydrite

  4. Zlnorsper

Show answer
Correct Option: D
Explanation:

Gypsum is calcium sulphate dihydrate $(CaSO _4 \cdot 2H _2O)$. Zlnorsper is not chemically similar to gypsum.

Potash magnerin is:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. $KCO _{ 3}.MgCO _{ 3} .5H _{2} O$

  2. $K _{2} SO _{4} .MgSO _{4} .6H _{2} O$

  3. $KCl.MgCl _{2} .6H _{2} O$

  4. none

Show answer
Correct Option: B
Explanation:

The formula of Potash magnerin is $K _{2} SO _{4} .MgSO _{4} .6H _{2} O$

Dead burnt plaster is :

some important compounds of magnesium and calcium the s-block elements chemistry

  1. ${ CaSO } _{ 4 }.{ 2H } _{ 2 }O$

  2. ${ MgSO } _{ 4 }.7{ H } _{ 2 }O$

  3. ${ CaSO } _{ 4 }.1/2{ H } _{ 2 }O$

  4. ${ CaSO } _{ 4 }$

Show answer
Correct Option: D
Explanation:

When Plaster of Paris $CaSO _4.\dfrac{1}{2}H _2O$ is heated above 393 K, its water of crystallisation is lost and anhydrous Calcium sulphate is left that is known as a dead burnt plaster.

Hence option D is correct answer.

When heated in steam, Mg burns brilliantly producing:

some important compounds of magnesium and calcium the s-block elements chemistry

  1. $Mg(OH) _2$

  2. $MgO and H _2$

  3. $MgO and O _2$

  4. $MgO and O _3$

Show answer
Correct Option: B
Explanation:

Magnesium burns in steam to produce white magnesium oxide and hydrogen gas. Very clean magnesium ribbon has a very slight reaction with cold water. After several minutes, some bubbles of hydrogen form on its surface, and the coil ofmagnesium ribbon usually floats to the surface.

The reaction occurs is,
$Mg+H _2O (g) \rightarrow MgO +H _2$

Hence option B is correct answer.

Which of the following is called milk of magnesia?

some important compounds of magnesium and calcium the s-block elements chemistry

  1. Suspension of ${\rm{Mg}}{\left( {{\rm{OH}}} \right) _{\rm{2}}}$

  2. Solution of ${\rm{MgS}}{{\rm{O}} _4}$

  3. Suspension of ${\rm{Mg}}$

  4. Solution of ${\rm{Mg}}{\left( {{\rm{HC}}{{\rm{O}} _3}} \right) _2}$

Show answer
Correct Option: A
Explanation:

Magnesium hydroxide is the inorganic compound with the chemical formula Mg(OH)₂. It occurs in nature as the mineral brucite.

Milk of magnesia contains magnesium, which is a naturally occurring mineral. The human body requires magnesium to help many of its systems function properly, most notably the muscles and the nerves.

Product (S) are :

$Mg _2C _3 {\xrightarrow []{D _2O} } \,\, { \xrightarrow[2.H _2O/\bar{O}H]{1.BH _3.THf}} \,\,{\xrightarrow {H _2/Ni} }\,\, \xrightarrow[\Delta]{Conc.H _3PO _4} (S)$

some important compounds of magnesium and calcium the s-block elements chemistry

  1. ${\text{H}}\mathop {\text{C}}\limits _{\mathop {\text{D}}\limits^{\text{|}} } = {\text{CH - C}}{{\text{D}} _{\text{3}}}$

  2. ${{\text{H}} _2}\mathop {\text{C}}\limits _{\mathop {\text{D}}\limits^{\text{|}} } - {\text{CH}}\;{\text{ = }}\;{\text{C}}{{\text{D}} _2}\;\;$

  3. ${{\text{H}} _{\text{2}}}{\text{C}}\; = {\text{CH - C}}{{\text{H}} _{\text{3}}}$

  4. ${{\text{H}} _{\text{2}}}{\text{C}} = \mathop {\text{C}}\limits _{\mathop {\text{D}}\limits^{\text{|}} } - {\text{C}}{{\text{H}} _{\text{3}}}$

Show answer
Correct Option: A