Tag: division of numbers

Questions Related to division of numbers

Find the remainder when $105!$ is divided by $214.$ 

  1. $168$

  2. $108$

  3. $196$

  4. $172$


Correct Option: B

Evaluate: $625\div 125$

  1. $125$

  2. $25$

  3. $31$

  4. $5$


Correct Option: D
Explanation:
The natural number $625$ can be divided by another natural number $125$ as follows:

$625\div 125=\dfrac { 625 }{ 125 } =5$

Hence, $625\div 125=5$

$\displaystyle  50 -\frac { 1 }{ 4 }\times  ........ =0$ 

  1. $\displaystyle \frac { 199 }{ 4 }$

  2. $\displaystyle \frac { 1 }{ 4 }$

  3. 200

  4. 0


Correct Option: C
Explanation:

50-x/4=0

50=x/4
x=50*4
x=200
hence option C is correct..

$\displaystyle 40-  \frac { 1 }{ 2 }\times ........ = 1 $ 

  1. $\displaystyle \frac { 79 }{ 2 }$

  2. 79

  3. $\displaystyle \frac { 2 }{ 79 }$

  4. $78$


Correct Option: D
Explanation:

40-x/2=1

40-1=x/2
39=x/2
x=39*2
x=78

Evaluate: $625\div 5=$

  1. $125$

  2. $25$

  3. $234$

  4. $35$


Correct Option: A
Explanation:
The natural number $625$ can be divided by another natural number $5$ as follows:

$625\div 5=\dfrac { 625 }{ 5 } =125$

Hence, $625\div 5=125$

Evaluate: $625\div 25$

  1. $125$

  2. $25$

  3. $35$

  4. $10$


Correct Option: B
Explanation:
The natural number $625$ can be divided by another natural number $25$ as follows:

$625\div 25=\dfrac { 625 }{ 25 } =25$

Hence, $625\div 25=25$

$\frac {171\tfrac {3}{4}\times 171\tfrac {3}{4}-91\tfrac {3}{4}\times 91\tfrac {3}{4}}{171\tfrac {3}{4}+91\tfrac {3}{4}}$ is equal to

  1. $263\frac {1}{2}$

  2. $90\frac {1}{4}$

  3. $80$

  4. $80\frac {3}{4}$


Correct Option: C
Explanation:

If $a=171\frac {3}{4}, b=91\frac {3}{4}$, then given expression is


$\dfrac {a^2-b^2}{a+b}=\dfrac {(a+b)(a-b)}{(a + b)}=a-b=171\frac {3}{4}-91\frac {3}{4}=80$