Tag: hydroxy compounds and ethers
Questions Related to hydroxy compounds and ethers
Oxygen atom of ether is:
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very active
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replaceable
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active
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comparatively inert
$C _2H _5-O-C _2H _5 + HI \xrightarrow {?} C _2H _5-OH + C _2H _5-I$
Identify the reaction condition, in which reaction occur.
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High temperature
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High vaccum
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Cold
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None of the above
The cleavage of ethers takes places with concentration $HI$ or $HBr$ at high temperature.
Diethyl ether can be decomposed with:
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$HI$
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$KMnO _4$
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$NaOH$
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$H _2O$
On heating with concentrated Hydrogen iodide $(HI)$ the C-O bond in ethers breaks forming alcohol and alkyl iodide. For example,
${ C } _{ 2 }{ H } _{ 5 }-O-{ C } _{ 2 }{ H } _{ 5 }+HI\longrightarrow { C } _{ 2 }{ H } _{ 5 }-I+{ C } _{ 2 }{ H } _{ 5 }OH$
On boiling with excess of concentrated Hydrogen iodide $(HI)$, Alkyl iodide is formed.
${ C } _{ 2 }{ H } _{ 5 }-O-{ C } _{ 2 }{ H } _{ 5 }+2HI\longrightarrow 2{ C } _{ 2 }{ H } _{ 5 }-I+{ H } _{ 2 }O$
When an ether is treated with $P _2S _5$, it gives:
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thioalcohol
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thioether
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thioester
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thioacetal
When an ether is treated with $P _2S _5$, it gives thioether.
Ethers are heated with excess of conc. hydrogen halide to give alkyl halide, then the reactivity order of hydrogen halide is :
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$HCl < HBr < HF$
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$HI > HBr > HCl $
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$HF < HCl < HBr $
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none of these
When $HX$ is in excess and reaction is carried out at high temperature. Iodine is a good nucleophile, displaces an alcohol molecule by $SN^2$ mechanism thus $HI>HBr>HCl$
Ethyl phenyl ether on boiling with conc. HBr gives:
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phenol and ethane
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bromobenzene and ethane
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phenol and ethyl bromide
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bromobenzene and ethanol
Alcohols of low molecular weight are:
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soluble in water
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soluble in water on heating
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insoluble in water
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insoluble in all solvents.
Alcohols of low molecular weight are soluble in water while that of high molecular weight are insoluble in water .because of high hydrogen bonding in low molecular weight Alcinous.
Which of the following statements is not correctly showing the trend of the properties mentioned ?
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$CH _3CH _2OH > CH _3CH _2CH _2OH > \underset {(Solubility)}{CH _3CH _2CH _2CH _2OH}$
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$CH _3CH _2OH > CH _3CH _2CH _2OH > \underset {(Boiling point)}{CH _3CH _2CH _2CH _2OH}$
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$CH _3CH _2CH _2OH > CH _3{\underset{CH _3}{\underset{|}{CH}}}-CH _2OH >\underset{Boiling \, point}{CH _3-\underset{CH _3}{\underset{|}{\overset{CH _3}{\overset{|}C}}}-OH}$
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$CH _3-{\underset{CH _3}{\underset{|}{\overset{CH _3}{\overset{|}{C}}}}}-OH$<$CH _3{\underset{CH _3}{\underset{|}{CH}}}-CH _2OH$ <$CH _3CH _2CH _CH _2OH$
Which of the following is not a characteristic of alcohol ?
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They are lighter than water.
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Their boiling points rise fairly uniformly with rising molecular weight.
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Lower members are insoluble in water and organic solvents but the solubility regularly increases with molecular mass.
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Lower members have a pleasant smell and burning taste, higher members are colourless and tasteless.
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Higher members have a pleasant smell and burning taste, lower members are colourless and tasteless.
Unlike phenol, 2,4-dinitrophenol is soluble in sodium carbonate solution in water because ?
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presence of two - $NO _2$ groups in the ring makes 2 , 4 - dinitrophenol a stronger acid than phenol.
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presence of two - $NO _2$ groups in the ring makes 2 , 4 - dinitrophenol a weaker acid than phenol.
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presence of two $-NO _2$ groups make the hydrogen bonding easier, making 2 , 4-dinitrophenol soluble.
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nitro group reacts with $Na _2CO _3$ while -$OH$ group does not.
Presence of two electron withdrawing $-No _2$ groups in the ring makes 2,4-dinitrophenol a stronger acid than phenol. Hence it react with aqueous $Na _2CO _3$ solution to form sodium salt thus making it soluble in $Na _2CO _3$ .