Questions Related to amines

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

State, whether the following statements are True or False:
Aniline forms phenol when treated with nitrous acid.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When aniline is treated with nitrous acid (HNO2) at low temperatures (273-278 K), it forms a stable benzenediazonium salt. Only at higher temperatures does the diazonium salt hydrolyze to form phenol. Thus, the direct statement that aniline forms phenol under standard diazotization conditions is false.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following amines form unstable diazonium salt?

  1. ${ C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }$
  2. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 2 }NH$
  3. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 3 }N$
  4. ${ CH } _{ 3 }{ NHC } _{ 2 }{ H } _{ 5 }$
Reveal answer Fill a bubble to check yourself
B,C,D Correct answer
Explanation

Only primary aromatic amines form stable arene diazonium salts.
The reaction is as follows:

$C _{6}H _{5}NH _{2} + NaNO _{2} + HCl (0-5^{\circ}C) \rightarrow PhN _{2}^{+}Cl^{-}$

Remain forms the unstable diazonium salt.
So, the correct options are $B$, $C$, $D$

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Reaction at ${ 0-5 }^{ 0 }C$ between aniline, ${ NaNO } { 2 }$ and HCl is known as___________

  1. Suphonation of benzene

  2. Acylation of aniline

  3. Alkylation of aniline

  4. Diazotisation

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

This is the diazotization reaction.


The reaction goes as follows :
$PhNH _{2} + NaNO _{2} + HCl \rightarrow PhN _{2}^{+} Cl^{-}$

The benzendiazonium salt thus formed acts as a synthetic intermediate and can be used to synthesize a wide variety of substituted benzene compounds.

For example,
$PhN _{2}^{+} Cl^{-} + CuCN \rightarrow PhCN$ (cyanobenzene)
$PhN _{2}^{+} Cl^{-} + CuI (KI) \rightarrow PhI$ (iodobenzene)

Option D is correct.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Aniline when treated with $NaNO { 2 }$ and $HCl$ at $0- { 5 }^{ 0 }C$ gives ___________ as a product.

  1. chloroaniline

  2. benzene diazonium chloride

  3. chlorobenzene

  4. dichlorobenzene

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Aniline reacts with sodium nitrite and HCl in cold condition to form benzene diazonium chloride.
$\underset {aniline} {{ C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }}\xrightarrow [ { NaNO } _{ 2 } ]{ HCl } \underset {benzene diazonium chloride} {[C _6H _5-N _2^+Cl^-]}$

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following amines will form stable diazonium salt at 273-283 K? 

  1. $\displaystyle { C } _{ 2 }{ H } _{ 5 }{ NH } _{ 2 }$
  2. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }$
  3. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ CH } _{ 2 }{ NH } _{ 2 }$
  4. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ N\left( { CH } _{ 3 } \right) } _{ 2 }$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Aniline (C6H5NH2) is a primary aromatic amine, which reacts with nitrous acid at 273-278 K to form benzenediazonium chloride, which is relatively stable at this temperature due to resonance. Aliphatic amines like C2H5NH2 and C6H5CH2NH2 form highly unstable diazonium salts that decompose immediately, while tertiary aromatic amines like C6H5N(CH3)2 undergo electrophilic aromatic substitution (nitrosation) instead of diazotization.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Diazonium salts are used at a very lower temperature because:

  1. they are poisonous at room temperature

  2. they are highly unstable at room temperature

  3. they are highly volatile at room temperature

  4. none of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Diazonium salt is used at very low temperature because of the fact that at the higher temperature they are unstable, as at higher temperature $N _2$ can leave out.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Diazonium salts are used:

  1. after storing for a few days after preparation

  2. immediately after its preparation

  3. after storing for $2-3$ hours
  4. difficult to prepare commercially

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Diazonium salts are light sensitive and break down under near UV or violet light.This is why it is used immedietly after being prepared so that it does not loses its properties.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

What makes diazonium ion one of the best leaving group of organic chemistry? 

  1. Half filled electronic configuration of nitrogen atom

  2. High electronegativity of nitrogen atom

  3. Very high stability of dinitrogen molecule in the atmosphere

  4. Weaker $C-N$ bond
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Diazonium ion is one of best leaving group of organic chemistry because of very high stability of dinitrogen molecule in the atmosphere.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts
What is the molarity of 0.2 N Na2 CO3 solution ?
  1. 0.1M

  2. 0M

  3. 0.4M

  4. 0.2M

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Normality is equal to molarity multiplied by the n-factor. For sodium carbonate (Na2CO3), the n-factor is 2 because it dissociates to release two sodium ions. Thus, a 0.2 N solution has a molarity of 0.2 / 2 = 0.1 M.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Diazomethane was photolysed to generate singlet carbine which was treated with cis-2-butene. The main product(s) of the reaction is/are:

  1. cis-1, 2-dimethylcyclopropane

  2. trans-1, 2-dimethylcyclopropane

  3. mixture of $(A)$ and $(B)$
  4. Ethylcyclopropane

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solution:- (A) cis-$1,2$-dimethylcyclopropane

$\underset{\text{Diazomethane}}{C{H} _{2}-\overset{+}{N}={N}^{-}} \xrightarrow[-N \equiv N]{h \nu} \underset{\text{Singlet carbene} \left( \text{Methylene} \right)}{:C{H} _{2}}$
The addition of methylene would yield trans-$1,2$-dimethylcyclopropane from trans-$2$-butene and cis-$1,2$-dimethylcyclopropane from cis-$2$-butene.