Tag: four operations

Questions Related to four operations

The given below input rearranges step-by-step in particular order according to a set of rules. In this case the last step of arranged input is Step V.
Input :  85 16 36 04 19 97 63 09 
Step I :  97 85 16 36 04 19 63 09
Step II : 97 85 63 16 36 04 19 09
Step III : 97 85 63 36 16 04 19 09
Step IV : 97 85 63 36 19 16 04 09
Step V : 97 85 63 36 19 16 09 04
Study the above arrangement carefully and then answer the following question.
Which of the following will be step III for their input below?
Input : 09 25 16 30 32 18 17 06

  1. 32 30 25 09 16 18 17 06

  2. 32 30 09 25 16 18 17 06

  3. 32 09 25 16 30 18 17 06

  4. 32 30 09 25 16 19 17 08


Correct Option: A
Explanation:

In every step, the series progresses towards getting its elements arranged in a descending order.
So, in every step, the largest elements of the input come to the front.
Input : 09 25 16 30 32 18 17 06
Step I:32 09 25 16 30 18 17 06
Step II:32 30 09 25 16 18 17 06
Step III:32 30 25 09 16  18 17 06
Hence option A is answer.

$n^2+n+1$ is a or an ______ number for all $n\in N$

  1. even

  2. odd

  3. prime

  4. none of these


Correct Option: B
Explanation:

Consider $ {n}^{2} + n = n(n+1) $ 

We know that if $ n $ is a number , then $ n  +1 $ will be its consecutive number

And product of a number and its consecutive number is always even. For example, $ 2 \times 3 = 6 ; 9 \times 10 = 90 $

And as  $ {n}^{2} + n$ is an even number.  Then
$ {n}^{2} + n + 1 $ will be the next consecutive number of the even number , which is an odd number.

Hence, $ {n}^{2} + n + 1 $ will always be an odd number for all natural numbers.

$\displaystyle \frac {11}{4}$ is a number between

  1. $1 \ and \ 2$

  2. $2 \ and \ 3$

  3. $3\  and \ 4$

  4. $11\  and \ 12$


Correct Option: B
Explanation:

$\displaystyle \frac {11}{4}\, =\, 2\displaystyle \frac {3}{4}$
So $\displaystyle \frac {11}{4}$ lies between $2$ and $3.$

Select the correct order for defining the following terms:
I - natural number
II - imaginary number
III - rational number
IV - integer

  1. I, IV, III, II

  2. I, II, III, IV

  3. I, III, II, IV

  4. IV, I, III, II

  5. I, IV, II, III


Correct Option: A
Explanation:
  • Here natural numbers are subset of integers , integers are subset of rational numbers and rational numbers are subset of imaginary numbers
  • Therefore the correct order of defining them is shown in option $A$

(0 , - 3 ) lies on _______ .

  1. Positive x- axis

  2. Negative x-axis

  3. Positive y-axis

  4. Negative y- axis


Correct Option: D
Explanation:

Given Coordinate of Point $P$ are $(0 , -3)$


$x-coordinate = 0$
$y-coordinate = -3$

$\Rightarrow$ Point $P$ lies of y-axis

Also, As $y-coordinate < 0$
Point $P (0 , -3)$ lies on Negative y- axis.

The number of surjections from $A = {1, 2,.....n}, n \leq 2$, onto B = {a, b} is

  1. $^nP _2$

  2. $2^n - 2$

  3. $2^n - 1$

  4. none of these


Correct Option: B
Explanation:

A = {1, 2, 3, ........, n}

B = {a, b}
A has n elements.
B has 2 elements.
$\therefore$ No. of surjection is $2^{n}-2$.

In the number $5\ast 436\ast 2$. the same digit occurs in place of $\ast $. The difference between their place values is $699930$. Which digit is in the place of $\ast $?

  1. $9$

  2. $8$

  3. $7$

  4. $1$


Correct Option: A

Find the number $94534$ how many times is the place value of the digit $4$ on the ratio so that of the left?

  1. $100$

  2. $\dfrac {1}{1000}$

  3. $\dfrac {1}{100}$

  4. $1000$


Correct Option: A

Choose the correct answers from the alternatives given.
$9^6$ -  11 when divided by 8 would leave a remainder of _______________.

  1. 0

  2. 6

  3. 2

  4. 3


Correct Option: B