Tag: space research and satellites

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Questions Related to space research and satellites

Multiple choice physics search of life outside earth space research and satellites artificial satellites space missions and artificial satellites

______________________is a CMOS camera, performed mineralogical mapping in the 400900 nm band with a spectral resolution of 15 nm and a spatial resolution of 80 m.

  1. HEX

  2. Hyper Spectral Imager

  3. Moon Impact Probe

  4. none of the above
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The scientific payload in Chandrayaan contained 5 Indian Instruments and 6 instruments from other countries.

Hyper Spectral Imager (HY SI), one of the Indian instruments, is a CMOS camera that performed mineralogical mapping in the 400-900 nm band with a spectral resolution of 15 nm and a spatial resolution of 80 m.

Multiple choice physics search of life outside earth space research and satellites artificial satellites space missions and artificial satellites

Which of the following Indian instruments were used in chandrayaan?

  1. TMC

  2. LLRI

  3. HEX

  4. all of the above
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The scientific payload in Chandrayaan contained 5 Indian instruments and 6 instruments from other countries.

The Indian instruments used in Chandrayaan were Terrain Mapping Camera (TMC), Hyper Spectral Imager (Hy SI), Lunar Laser Ranging Instrument (LLRI), High Energy aj/gamma X-ray Spectrometer (HEX) and Moon Impact Probe (MIP).

Multiple choice physics search of life outside earth space research and satellites artificial satellites space missions and artificial satellites

The specifications of chandrayaan include which of the following?

  1. 1380 Kg in mass.

  2. Cuboidal in shape

  3. Fuel and oxidiser were stored in two tanks of 390 litres each.

  4. all of the above
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The mass of Chandrayaan was 1380 kg at launch, 675 kg at lunar orbit and 523 kg after releasing the impactor. It was cuboidal in shape. The spacecraft used a bipropellant  integrating propulsion system to reach lunar orbit as well as its maintenance while operating the moon. The power plant consisted of one 440 N engine and eight 220 thrusters. Fuel and oxidiser were stored in two tanks of 390 litres each.

Multiple choice physics search of life outside earth space research and satellites artificial satellites space missions and artificial satellites

The Chandrayaan used a _______________ integrated propulsion system to reach lunar orbit as well as orbit and altitude maintenance while orbiting the Moon.

  1. tripropellent

  2. bipropellant

  3. two star sensors

  4. none of the above
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

 The Chandrayaan used a bipropellant  integrating propulsion system to reach lunar orbit as well as orbit and altitude maintenance while operating the Moon. The power plant consisted of one 440 N engine and eight 220 thrusters. Fuel and oxidiser were stored in two tanks of 390 litres each.

Multiple choice physics search of life outside earth space research and satellites artificial satellites space missions and artificial satellites

The Chandrayaan was mainly powered by its solar array, which included one solar panel covering a total area of 2.15 x 1.8 m generating 750 W of peak power, which was stored in a_____________ for use during eclipses.

  1. cadmium zinc battery

  2. lead ion battery

  3. 36 Ah lithium-ion battery

  4. none of the above
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The Chandrayaan was mainly powered by its solar array, which included one solar panel covering a total area of 2.15 x 1.8 m generating 750 W of peak power, which was stored in a 36 Ah lithium-ion battery for use during eclipses.

Multiple choice physics observing space: telescopes space research and satellites space travel space exploration and forms of light

The angular resolution of a 10cm diameter telescope at a wavelength of $5000 A^0$ is of the order of -

  1. $10^{4} rad$
  2. $10^{-6} rad$
  3. $10^{6} rad$
  4. $10^{2} rad$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Given parameters are,

Wavelength $\lambda = 5000\ A^{\circ}$

 = $5000 \times 10^{-10}$

Diameter of telescope, $D = 10 cm = 0.1 m$

Now, Angular resolution (d\theta) formula for telescope is,

$d\theta =\dfrac{1.22 \lambda}{D}\\$

Substituting the values, we get

$\Rightarrow d\theta = \dfrac{1.22 \times 5000 \times 10^{-10}}{0.1}= 6.1 \times 10^{-6}\\$

Clearly it is having significance order of $10^{-6}$.

Thus option B is correct.

Multiple choice physics observing space: telescopes space research and satellites space travel space exploration and forms of light

An observer looks at a distant tree of height $10$ m with a telescope magnifying power of $20$. To the observer, the top appears

  1. 10 times taller

  2. 10 times nearer

  3. 20 times taller

  4. 20 times nearer
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A telescope with a magnifying power of 20 makes distant objects appear 20 times closer (or 20 times larger in angular size).

Multiple choice physics observing space: telescopes space research and satellites space travel space exploration and forms of light

The focal length of eye lens and object lens of a telescope is 4 mm and 4 cm respectively. If final image of an far object is at $\infty $. Then the magnifying power and length of the tube are :

  1. 10, 4.4 cm

  2. 4, 44 cm

  3. 44,10 cm

  4. 10, 44 cm
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Answer is A.

Magnification is the amount that a telescope enlarges its subject. Its equal to the telescopes focal length divided by the eyepieces focal length. As a rule of thumb, a telescopes maximum useful magnification is 50 times its aperture in inches (or twice its aperture in millimeters). 
That is, M = fo / fe
In this case, the focal length of eye lens and object lens of a telescope is 4 mm = 0.4 cm and 4 cm respectively.
So, Magnification M = fo / fe = 4 / 0.4 = 10.
Focal length of the eyepiece is the distance from the center of the eyepiece lens to the point at which light passing through the lens is brought to a focus.
Focal length of the objective is the distance from the center of the objective lens (or mirror) to the point at which incoming light is brought to a focus.
The length of the tube is given as sum of the focal lengths of the eye lens and the object lens.
So, Length of the tube  = fo + fe = 4 + 0.4 = 4.4 cm.
Hence, the magnifying power and length of the tube are: 10, 4.4 cm.

Multiple choice physics observing space: telescopes space research and satellites space travel space exploration and forms of light

Which of the following is correct about astronomical telescope?

  1. It consists of two diverging lenses

  2. Its objective is a concave lens

  3. Its eyepiece is a convex lens with greater focal length than the objective

  4. The final image in this telescope is inverted
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Since in astronomical telescopes we are not much bothered about the inverted carterer. So, we get final image in this telescope is inverted where in terrestrial, we get upright image.

Multiple choice physics observing space: telescopes space research and satellites space travel space exploration and forms of light

Telescopic aids are used:

  1. to view planets and other astronomical activities

  2. to view chalkboards and class demonstrations

  3. for performing computational tasks

  4. helps visuaaly challenged people in reading and writing
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Telescopic aids comes under optical aids.Telescopic aids are available to view chalkboards and class demonstrations