Tag: introduction to hydrogen

Questions Related to introduction to hydrogen

Water gas is mixed with steam and the mixture is passed over heated $Fe _{2}O _{3}$ in presence of $Cr _{2}O _{3}.$
The mixture when passed in water dissolves $CO _{2}$ and dihydro gen left undissolved is collected. This method of preparation of hydrogen gas is known as:

chemistry study of the first element - hydrogen occurrence of hydrogen introduction to hydrogen hydrogen

  1. Bosch process

  2. Lane process

  3. Kellner process

  4. Hall process

Show answer
Correct Option: A
Explanation:

For the commercial preparation of dihydrogen, Bosch process is used.


In Bosch's process, water gas (i.e. $CO+H _2$ ) is mixed with twice of its volume of steam in presence of catalysts $Fe _2O _3$ and $Cr _2O _3$ or $ThO _2$ where $Cr _2O _3$ acts as promoter. It gives the products $CO _2$ and $H _2$. Now, $CO _2$ is dissolved in water & removed leaving $H _2$ behind which is undissolved.

hydrogen peroxid  is not produced by the reaction :-

chemistry study of the first element - hydrogen occurrence of hydrogen introduction to hydrogen hydrogen

  1. $Na _2O _2 + dil.H _2SO _4$

  2. $Mg + H _2O$

  3. $BaO _2 + HCl$

  4. $BaO _2 + H _3PO _4$

Show answer
Correct Option: B
Explanation:

Sodium peroxide $\left( { Na } _{ 2 }{ O } _{ 2 } \right) $, when it reacts with sulphuric acid $\left( { H } _{ 2 }{ SO } _{ 4 } \right) $, it leads to the formation of sodium sulphate $\left( { Na } _{ 2 }{ SO } _{ 4 } \right) $ with hydrogen peroxide $\left( { H } _{ 2 }{ O } _{ 2 } \right) $.

${ Na } _{ 2 }{ O } _{ 2 }+{ H } _{ 2 }{ SO } _{ 4 }\longrightarrow { Na } _{ 2 }{ SO } _{ 4 }+{ H } _{ 2 }{ O } _{ 2 }$
Also, $Mg+{ H } _{ 2 }O\longrightarrow { Mg\left( OH \right)  } _{ 2 }$
${ BaO } _{ 2 }+HCl\longrightarrow Ba{ Cl } _{ 2 }+{ H } _{ 2 }{ O } _{ 2 }$
${ BaO } _{ 2 }+{ H } _{ 3 }{ PO } _{ 4 }\longrightarrow { Ba } _{ 3 }{ \left( { PO } _{ 4 } \right)  } _{ 2 }+{ H } _{ 2 }{ O } _{ 2 }$
Thus, in all of the above reactions, hydrogen peroxide $\left( { H } _{ 2 }{ O } _{ 2 } \right) $ is formed.