Self fertilising trihybrid plants form
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Eight different gametes and 64 different zygotes
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Four different gametes and sixteen different zygotes
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Eight different gametes and sixteen different zygotes
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Eight different gametes and thirty two different zygotes
A total number of types of gamete produced by an organism is 2$^n$, where n is the number of heterozygous genes present. As we know that trihybrid plant is heterozygous for three genes, these total possible gametes by it = 2$^3$ = 8. During fertilization, any of the 8 types of sperms can fuse with any of the 8 types of egg to produce 64 possible combinations of zygotes. This makes option A correct but C and D wrong. Four different types of gametes are produced by an organism who is heterozygous for two genes; 2$^2$ = 4 and resultant four gametes produce total 4 x 4 = 16 zygotic combinations. Thus, option B is wrong.