Tag: superposition of waves

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Questions Related to superposition of waves

Multiple choice physics superposition of waves difference between interference and diffraction explaining wave phenomena diffraction

Two wave-fronts are emitted from coherent sources of path difference between them is $2.1$ micron. Phase difference between the wave-fronts at that point is $7.692\ \pi$. Wavelength of light emitted by sources will be :

  1. $5386\mathring{A}$

  2. $5400\mathring{A}$

  3. $5460\mathring{A}$

  4. $5892\mathring{A}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Given:
$\Delta x=2.1 \times 10^{-6}\\\Delta \phi=7.6922$

$\Phi =\dfrac{2\pi \Delta x}{\lambda}$

$\lambda=\dfrac{2\pi\times 2.1\times 10^{-6}}{7.692\pi}$

$\lambda=5460\times 10^{-10}m$
Multiple choice physics superposition of waves difference between interference and diffraction explaining wave phenomena diffraction

The sodium yellow doublet has wavelengths $5890\mathring{A}$ and $'\lambda' \mathring{A}$ and resolving power of a grating to resolve these lines is $982$, then value of $\lambda$ is :

  1. $5896\mathring{A}$

  2. $5880\mathring{A}$

  3. $5869\mathring{A}$

  4. $5876\mathring{A}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Resolving power R = lambda / delta_lambda = n * N. Given R = 982, lambda = 5890, delta_lambda = 5896 - 5890 = 6. R = 5890 / 6 = 981.6, which is approximately 982.