Tag: evs

Questions Related to evs

A satellite placed in an orbit around Earth with certain speed will revolve in_______ as seen from Earth

  1. A helical path

  2. A circular path

  3. Straight line

  4. A parabolic path


Correct Option: B
Explanation:

The centrifugal force acting on the satellite, revolving around the earth with certain velocity, is balanced by the gravitational force acting on it due to earth. The satellite keeps revolving around the earth in circular path of certain radius as seen from the earth.

Moon can be classified as a

  1. Asteroid

  2. Comet

  3. Satellite

  4. Star


Correct Option: C
Explanation:

Moon revolves around earth with certain fixed velocity in a circular orbit of certain radius. Moon is a natural satellite of earth whose time period of revolution is $27.3$ days.

It is possible to put an artificial satellite into orbit in such a way that it will always remain directly over New Delhi.

  1. True

  2. False


Correct Option: A

Parking orbit for a geostationary satellite is

  1. at 45 degrees north west of equator

  2. is in equatorial plane of earth

  3. in west-east direction.

  4. along the north direction


Correct Option: B
Explanation:

Parking orbit for a geostationary satellite is in equatorial plane of earth, since it has to be at rest always with respect to equator

The correct option is option (b)

A geostationary satellite is at rest, relative to earth only for points in the 

  1. equitorial plane

  2. plane passing through the poles of the earth

  3. plane along magnetic north and south of the earth

  4. planes that are isoclinic


Correct Option: A
Explanation:

A geostationary satellite is at rest, relative to earth only for points in the equitorial plane.

The correct option is (a)

The speed of a geostationary satellite relative to a person on the earth is 

  1. Zero

  2. 2 km/s

  3. 10 km/s

  4. 8 km/s


Correct Option: A
Explanation:

A geostationary satellite is a satellite which always appears to be stationary from an earth's surface.

The correct option is option (a)

Time period of a simple pendulum inside a satellite orbiting earth is

  1. Zero

  2. $\infty$

  3. $T$

  4. $2T$


Correct Option: B
Explanation:

As we know, $T\alpha \dfrac { 1 }{ \sqrt { g }  } $

On a artificial satellite, orbiting the earth, neg gravity is zero. As,
$\Rightarrow \quad g=0\Rightarrow T\rightarrow \infty $
$\Rightarrow$  Option B is the correct answer.

Two satellites of masses $m _{1}$ and $m _{2} (m _{1} > m _{2})$ are revolving round the earth in circular orbits of radii $r _{1}$ and $r _{2}(r _{1} > r _{2})$ respectively. Which of the following statements is true regarding their speeds $v _{1}$ and $v _{2}$?

  1. $v _{1} = v _{2}$

  2. $v _{1} < v _{2}$

  3. $v _{1} > v _{2}$

  4. $(v _{1}/r _{1}) = (v _{2}/r _{2})$


Correct Option: B
Explanation:

Velocity of satellite $=\sqrt { \dfrac { GM }{ R+h }  } $

Now, 
        ${ V } _{ 1 }=\sqrt { \dfrac { GM }{ { r } _{ 1 } }  } $
        ${ V } _{ 2 }=\sqrt { \dfrac { GM }{ { r } _{ 2 } }  } $
As ${ r } _{ 1 }>{ r } _{ 2 }$
So  ${ V } _{ 1 }<{ V } _{ 2 }$

An artificial satellite is moving around earth in a circular orbit with speed equal to one fourth the escape speed of a body from the surface of earth. The height of satellite above earth is : ($R$ is radius of earth)

  1. $3R$

  2. $5R$

  3. $7R$

  4. $8R$


Correct Option: D
Explanation:
Let's consider,

$r=$ height  of the satellite above the earth

$R=$ radius of the earth

$G=$ gravitational constant

$g=$ acceleration due to gravity

The escape velocity of a body from the surface of earth,

$v _e=\sqrt{\dfrac{2GM}{R}}$

$\dfrac{1}{4}.v _e=\dfrac{1}{4}\sqrt{\dfrac{2GM}{R}}$. . . . . .(1)

The orbital velocity of the satellite is given by

$v _o=\sqrt{\dfrac{GM}{r}}$. . . . . .(2)

Equation equation (1) and (2), we get

$\sqrt{\dfrac{GM}{r}}=\dfrac{1}{4}\sqrt{\dfrac{2GM}{R}}$

$\dfrac{GM}{r}=\dfrac{1}{16}.\dfrac{2GM}{R}$

$r=8R$

The correct option is D.

A stationary object is released from a point $P$ at a distance $3R$ from the centre of the moon which has radius $R$ and mass $M$. Which of the following gives the speed of the object on hitting the moon?

  1. $\left (\dfrac {2GM}{3R}\right )^{1/2}$

  2. $\left (\dfrac {4GM}{3R}\right )^{1/2}$

  3. $\left (\dfrac {GM}{3R}\right )^{1/2}$

  4. $\left (\dfrac {GM}{R}\right )^{1/2}$


Correct Option: C