Tag: evs

• Plane mirrors always produce virtual images, because they never focus light into a single converging point.
• Hence it does not produce real object or image
  
• As power of the plane mirror is zero, hence, it neither converges nor diverges the rays.
• Hence the option C is the right answer

In this case, the mirror is moved 25 cm away from its initial position. Therefore, if the mirror is moved with distance x, then image in the mirror will move by distance 2x.
That is, 2x=50 cm.
So, the image will shift by 50 cm away from its previous position.

In plane mirrors the image formed is of the same size.

Answer is B.

The image formed by a plane mirror is always virtual (meaning that the light rays do not actually come from the image), upright, and of the same shape and size as the object it is reflecting. A virtual image is a copy of an object formed at the location from which the light rays appear to come.
To summarize, the image formed by plane mirrors are,
1. Virtual 
2. Behind the mirror 
3. Erect (means not inverted) 
4. Same size as the object 
5. At same distance from the mirror as the object is from the mirror.

Two plane mirrors are placed parallel in a periscope to reflect light. 

Images formed by plane mirrors are virtual, upright, left-right reversed, the same distance from the mirror as the object's distance, and the same size as the object.

An image, such as that seen in a mirror, in which the rays of light appear to be emanating from some object that is not there is called a virtual image. Virtual images are always erect. They, also, may be either larger or smaller than the object.
Hence, the statement is true.

Angle of incidence and the angle of reflection measured from the normal drawn on the point of incidence.

Answer is D.

For a spherically curved mirror in air, the magnitude of the focal length is equal to the radius of curvature of the mirror divided by two. The focal length is positive for a concave mirror.
Therefore, the focal length of the mirror is 20 cm / 2 = 10 cm.
The mirror equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f). The equation is stated as follows:
1/f = 1/do + 1/di
So, 1/di = 1/f - 1/do = 1/10 - 1/15
Therefore, di = 30 cm.
The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (hi) and object height (ho). The magnification equation is stated as follows:
M = hi / ho = -(di / do) = -(30 / 15) = -2.
Hence, the image magnification produced is -2.