Which of the following is not correct?
- ${\text{TiC}}{{\text{l}} _{\text{4}}}$ is a colourless compound.
- $\left[ {{\text{Cr}}{{\left( {{\text{N}}{{\text{H}} _{\text{3}}}} \right)} _{\text{6}}}} \right]{\text{C}}{{\text{L}} _{\text{3}}}$ is a coloured compound
- ${{\text{K}} _{\text{3}}}\left[ {{\text{V}}{{\text{F}} _{\text{6}}}} \right]$ is a colourless compound
- $\;\left[ {{\text{Cu}}{{\left( {{\text{NCC}}{{\text{H}} _{\text{3}}}} \right)} _{\text{4}}}} \right]\left[ {{\text{B}}{{\text{F}} _{\text{4}}}} \right]$ is a colourless compound
Reveal answer
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C
Correct answer
Explanation
Vanadium in K3[VF6] is in the +3 oxidation state with a d2 configuration and undergoes d-d transitions, making it colored. However, the statement claims it is a colourless compound, which is incorrect since many V(III) complexes show color. Therefore, option C describes the false statement.