Tag: enthalpy

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Questions Related to enthalpy

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

For the combustion reaction at $298\,K$
$2Ag(s) +1/2O _2(g)\longrightarrow 2Ag _2O(s)$ Which of the following alternative is correct?

  1. $\Delta H = \Delta U$
  2. $\Delta H > \Delta U$
  3. $\Delta H < \Delta U$
  4. $\Delta H and \Delta U$ bear no relation with each other
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

As we know,
$\,\Delta H = \Delta U + \Delta nRT$
$\Delta n = n _{ P } - n _{ R }$
$\therefore\Delta n = 2 \displaystyle - \frac { 5 }{ 2 } =\displaystyle -\frac{ 1 }{ 2 }$
$\therefore\Delta H = \Delta U \displaystyle - \frac { 1 }{ 2 }RT$
$\therefore\Delta U = \Delta H +\displaystyle \frac{ 1 }{ 2 }RT$
or $\therefore\Delta U > \Delta H$

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

Hess's law is based on:

  1. Law of conservation of mass

  2. Law of conservation of energy

  3. Second law of thermodynamics

  4. None of the above
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The Hess's law states that the total enthalpy change during the complete course of a chemical reaction is the same whether the reaction is made in one step or in several steps. Hess's law is now understood as an expression of the principle of conservation of energy, also expressed in the first law of thermodynamics, and the fact that the enthalpy of a chemical process is independent of the path taken from the initial to the final state (i.e. enthalpy is a state function).

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy
For a particular reaction ; $\Delta E$ $=\Delta H + P\Delta $V.

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The given statement is false.
For a particular reaction $\displaystyle \Delta H = \Delta  E + P \Delta  V$
The change in enthalpy is equal to the sum of the change in the internal energy and the pressure volume work. This expression is applicable at constant pressure.

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

Select the correct option(s):

  1. $q=nC _{v}\mathrm{d} T$ is applicable to all substances during heating/cooling at constant 'v'.
  2. $q=nC _{v}\mathrm{d} T$ is applicable to ideal gas during heating/cooling at constant 'v'.
  3. $\mathrm{d} U=nC _{v}\mathrm{d} T$ is applicable for real gas at constant 'v'
  4. $\mathrm{d} U=nC _{v}\mathrm{d} T$ is applicable for ideal gas at constant 'v' only
Reveal answer Fill a bubble to check yourself
A,B Correct answer
Explanation

An isochoric process is a thermodynamic process during which the volume of the closed system undergoing such a process remains constant. 


Work done by system is given as $W=P\Delta V$

So workdone by the ideal and real gases will be zero in all cases.

From first law of thermodynamics, $Q=W+\Delta U$
$\Longrightarrow Q=\Delta U$

$\Delta U=n{ C } _{ v }\Delta T$ is applicable for all conditions whether the volume is constant or not.

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

Enthalpy change of a reaction will be equal to:

  1. $\Delta U + P\Delta V$
  2. $\Delta U + V\Delta P$
  3. $\Delta U + \Delta (PV)$
  4. $\Delta U + (\Delta n _{ g } )\Delta (PV)$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The relationship between the enthalpy $H$, internal energy $E$, pressure $P$ and volume $V$ is $H=E+PV$
Hence, the expression for the enthalpy change becomes $\Delta H = \Delta U + \Delta (PV)$
Hence, the enthalpy change of a reaction will be equal to $\Delta U + \Delta (PV)$.

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

In an isothermal process:

  1. $q=0$ and $\Delta E=0$
  2. $q\neq 0$ and $\Delta E=0$
  3. $q=0$ and $\Delta E\neq 0$
  4. $q\neq 0$ and $\Delta E\neq 0$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0. In other words, in an isothermal process, the value ΔT = 0 and therefore the change in internal energy ΔU = 0 (only for an ideal gas) but Q ≠ 0, while in an adiabatic process, ΔT ≠ 0 but Q = 0.

Multiple choice chemistry enthalpy changes enthalpy changes and enthalpy profile diagrams enthalpy study of enthalpy

Two reactions are given below:

(i) $CO _{(g)} + \frac{1}{2}O _2{(g)} \rightarrow CO _2{(g)}$

(ii) $ Ag _2O _{(s)} \rightarrow 2Ag _{(s)} + \frac{1}{2}O _2{(g)}$

Which of the following statements is true?

  1. For (i) $\vartriangle$H < $\vartriangle$E and for (ii) $\vartriangle$H > $\vartriangle$E
  2. For (i) $\vartriangle$H > $\vartriangle$E and for (ii) $\vartriangle$H < $\vartriangle$E
  3. For both (i) and (ii) $\vartriangle$H > $\vartriangle$E
  4. For both (i) and (ii) $\vartriangle$H < $\vartriangle$E
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\Delta H=\Delta E+\Delta { n } _{ g }RT$ 


(i) $CO(g) + \cfrac { 1 }{ 2 } { O } _{ 2 }(g) \longrightarrow  C{ O } _{ 2 }(g)$

$ \quad   \Delta { n } _{ g }=1-\cfrac { 1 }{ 2 } -1=-\cfrac { 1 }{ 2 } <0$

$\therefore \Delta H<\Delta E$

(ii) ${ Ag } _{ 2 }O(s) \longrightarrow  2Ag(s) + \cfrac { 1 }{ 2 } { O } _{ 2 }(g)$

$\quad  \Delta { n } _{ g }=\cfrac { 1 }{ 2 } +0-0=\cfrac { 1 }{ 2 } >0$ 

$\therefore \Delta H>\Delta E$

So, the correct option is A.