Trigonometry Questions

Multiple choice
  1. $\displaystyle \frac{h \sin \alpha + a \cos \alpha}{9 \cos \alpha}$
  2. $\displaystyle \frac{h \cos \alpha - a \sin \alpha}{9 \sin \alpha}$
  3. $\displaystyle \frac{h \sin \alpha + a \cos \alpha}{9 \sin \alpha}$
  4. $\displaystyle \frac{h \cos \alpha - a \sin \alpha}{9 \cos \alpha}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the poles be at distances x1, x2, ..., x10 from O. tan(alpha) = h_i / x_i. x_i = h_i / tan(alpha). The distance between consecutive poles is (h_{i+1} - h_i) / tan(alpha). Using the geometry of the setup, the formula simplifies to the given expression.

Multiple choice
  1. $\sin {\theta}=\cfrac{P}{H}=\cfrac{4}{5}$

    $\cos {\theta}=\cfrac{B}{H}=\cfrac{4}{5}$

    $\tan {\theta}=\cfrac{P}{B}=\cfrac{4}{3}$

    $\cot{\theta}=\cfrac{B}{P}=\cfrac{3}{4}$

    $\sec {\theta}=\cfrac{H}{B}=\cfrac{5}{3}$

    $co\sec {\theta}=\cfrac{H}{P}=\cfrac{5}{4}$
  2. $\sin {\theta}=\cfrac{P}{H}=\cfrac{4}{5}$

    $\cos {\theta}=\cfrac{B}{H}=\cfrac{2}{5}$

    $\tan {\theta}=\cfrac{P}{B}=\cfrac{4}{3}$

    $\cot{\theta}=\cfrac{B}{P}=\cfrac{3}{4}$

    $\sec {\theta}=\cfrac{H}{B}=\cfrac{5}{3}$

    $co\sec {\theta}=\cfrac{H}{P}=\cfrac{5}{4}$
  3. $\sin {\theta}=\cfrac{P}{H}=\cfrac{4}{5}$

    $\cos {\theta}=\cfrac{B}{H}=\cfrac{1}{5}$

    $\tan {\theta}=\cfrac{P}{B}=\cfrac{4}{3}$

    $\cot{\theta}=\cfrac{B}{P}=\cfrac{3}{4}$

    $\sec {\theta}=\cfrac{H}{B}=\cfrac{5}{3}$

    $co\sec {\theta}=\cfrac{H}{P}=\cfrac{5}{4}$
  4. $\sin {\theta}=\cfrac{P}{H}=\cfrac{4}{5}$

    $\cos {\theta}=\cfrac{B}{H}=\cfrac{3}{5}$

    $\tan {\theta}=\cfrac{P}{B}=\cfrac{4}{3}$

    $\cot{\theta}=\cfrac{B}{P}=\cfrac{3}{4}$

    $\sec {\theta}=\cfrac{H}{B}=\cfrac{5}{3}$

    $co\sec {\theta}=\cfrac{H}{P}=\cfrac{5}{4}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice
  1. $\text{length of ladder}=7.4m$ , $\text{distance}=2.14m$
  2. $\text{length of ladder}=4.27m$ , $\text{distance}=3.7m$
  3. $\text{length of ladder}=4.27m$ , $\text{distance}=2.14m$
  4. $\text{length of ladder}=4.7m$ , $\text{distance}=2.14m$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Height to reach = 5 - 1.3 = 3.7m. Ladder length L = 3.7 / sin(60) = 3.7 / (sqrt(3)/2) = 7.4 / 1.73 = 4.277m. Distance from pole = 3.7 / tan(60) = 3.7 / 1.73 = 2.138m.

Multiple choice
  1. $A$ and $R$ both are true,$R$ is correct explanation for $A$
  2. Both $A$ and $R$ are true and $R$ is not correct explanation of $A$
  3. $A$ is true but $R$ is false
  4. $A$ is false but $R$ is true.
Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice
  1. Both $A$ and $R$ are ture and $R$ is the correct explanation of $A$
  2. Both $A$ and $R$ are true and  $R$ is not correct explanation of $A$
  3. $A$ is true but $R$ is false
  4. $A$ is false but $R$ is true.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The height h = d / (cot(30) - cot(45)) = 60 / (sqrt(3) - 1) = 60(sqrt(3)+1) / 2 = 30(sqrt(3)+1). Both the assertion and the reason are correct, and the reason provides the formula used in the assertion.

Multiple choice
  1. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

  2. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

  3. Assertion is correct but Reason is incorrect

  4. Assertion is incorrect but Reason is correct

Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice
  1. 1 : 1

  2. 3 : 1

  3. 1 : 2

  4. 2 : 1

  5. 1 : 3

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

In triangle PAB, tan(30) = H / 2a, so H = 2a * tan(30) = 2a / sqrt(3). In triangle QAC, tan(60) = (H+BC) / a, so H+BC = a * tan(60) = a * sqrt(3). Thus, BC = a * sqrt(3) - 2a / sqrt(3) = (3a - 2a) / sqrt(3) = a / sqrt(3). The ratio AB/BC = H/BC = (2a/sqrt(3)) / (a/sqrt(3)) = 2/1.