Mathematics
Trigonometric Identities
87 Questions
Trigonometric identities focus on solving equations using tangent, sine, and cosine properties. Questions involve half angle formulas and slope calculations. This topic is a staple in the quantitative aptitude section of major competitive examinations.
Tangent propertiesAngle formulasTrigonometric equationsHalf angle identitiesSlope calculations
Trigonometric Identities Questions
What is the value of (tan 45^\circ)?
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\(1\)
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\(\sqrt{2}\)
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\(\sqrt{3}\)
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\(2\)
A
Correct answer
Explanation
We know that (tan 45^\circ = 1).
What is the double angle formula for tangent?
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\(tan 2A = \frac{2 tan A}{1 - tan^2 A}\)
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\(tan 2A = tan A + tan A\)
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\(tan 2A = cos A + cos A\)
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\(tan 2A = 2 tan A sin A\)
A
Correct answer
Explanation
The double angle formula for tangent states that (tan 2A = \frac{2 tan A}{1 - tan^2 A}).
What is the half angle formula for tangent?
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\(tan \frac{A}{2} = \pm \sqrt{\frac{1 - cos A}{1 + cos A}}\)
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\(tan \frac{A}{2} = tan A + tan A\)
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\(tan \frac{A}{2} = cos A + cos A\)
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\(tan \frac{A}{2} = 2 tan A sin A\)
A
Correct answer
Explanation
The half angle formula for tangent states that (tan \frac{A}{2} = \pm \sqrt{\frac{1 - cos A}{1 + cos A}}).
Which of the following is an identity?
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sin^2(x) + cos^2(x) = 1
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sin(x) + cos(x) = 1
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sin(x) - cos(x) = 1
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sin(x) / cos(x) = tan(x)
A
Correct answer
Explanation
The identity sin^2(x) + cos^2(x) = 1 is known as the Pythagorean identity. It is true for all values of x.
Which of the following is the quotient identity for tangent?
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tan(x) = sin(x) / cos(x)
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tan(x) = cos(x) / sin(x)
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tan(x) = sin(x) + cos(x)
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tan(x) = cos(x) - sin(x)
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Correct answer
Explanation
The quotient identity for tangent is tan(x) = sin(x) / cos(x).
What is the sum-to-product identity for tangent?
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tan(x) + tan(y) = (sin(x+y))/(cos(x)cos(y))
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tan(x) + tan(y) = (sin(x-y))/(cos(x)cos(y))
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tan(x) + tan(y) = (cos(x+y))/(sin(x)sin(y))
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tan(x) + tan(y) = (cos(x-y))/(sin(x)sin(y))
A
Correct answer
Explanation
The sum-to-product identity for tangent is tan(x) + tan(y) = (sin(x+y))/(cos(x)cos(y)).
Which of the following is the difference-to-product identity for tangent?
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tan(x) - tan(y) = (sin(x-y))/(cos(x)cos(y))
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tan(x) - tan(y) = (sin(x+y))/(cos(x)cos(y))
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tan(x) - tan(y) = (cos(x-y))/(sin(x)sin(y))
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tan(x) - tan(y) = (cos(x+y))/(sin(x)sin(y))
A
Correct answer
Explanation
The difference-to-product identity for tangent is tan(x) - tan(y) = (sin(x-y))/(cos(x)cos(y)).
What is the half-angle identity for tangent?
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tan(x/2) = (1 - cos(x))/(1 + cos(x))
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tan(x/2) = (1 + cos(x))/(1 - cos(x))
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tan(x/2) = (sin(x))/(cos(x))
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tan(x/2) = (cos(x))/(sin(x))
A
Correct answer
Explanation
The half-angle identity for tangent is tan(x/2) = (1 - cos(x))/(1 + cos(x)).
Which of the following is the double-angle identity for tangent?
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tan(2x) = (2tan(x))/(1 - tan^2(x))
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tan(2x) = (2tan(x))/(1 + tan^2(x))
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tan(2x) = (tan(x))/(1 - tan^2(x))
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tan(2x) = (tan(x))/(1 + tan^2(x))
A
Correct answer
Explanation
The double-angle identity for tangent is tan(2x) = (2tan(x))/(1 - tan^2(x)).
Brahmagupta's formula for calculating the tangent of an angle is given by:
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$\tan A = \frac{\sin A}{\cos A}$
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$\tan A = \frac{\cos A}{\sin A}$
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$\tan A = \frac{\sin A}{\sec A}$
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$\tan A = \frac{\cos A}{\csc A}$
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Correct answer
Explanation
Brahmagupta's formula for tangent is derived from the definition of tangent.
Brahmagupta's formula for calculating the tangent of the sum of two angles is given by:
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$\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
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$\tan(A + B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
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$\tan(A + B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
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$\tan(A + B) = \frac{\cos A + \cos B}{\sin A + \sin B}$
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Correct answer
Explanation
Brahmagupta's formula for the tangent of the sum of two angles is derived from the angle addition formula for tangent.
Brahmagupta's formula for calculating the tangent of the difference of two angles is given by:
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$\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
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$\tan(A - B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
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$\tan(A - B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
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$\tan(A - B) = \frac{\cos A - \cos B}{\sin A - \sin B}$
A
Correct answer
Explanation
Brahmagupta's formula for the tangent of the difference of two angles is derived from the angle difference formula for tangent.