Mathematics
Trigonometric Identities
82 Questions
Trigonometric identities focus on solving equations using tangent, sine, and cosine properties. Questions involve half angle formulas and slope calculations. This topic is a staple in the quantitative aptitude section of major competitive examinations.
Tangent propertiesAngle formulasTrigonometric equationsHalf angle identitiesSlope calculations
Trigonometric Identities Questions
What is the sum-to-product identity for tangent?
-
tan(x) + tan(y) = (sin(x+y))/(cos(x)cos(y))
-
tan(x) + tan(y) = (sin(x-y))/(cos(x)cos(y))
-
tan(x) + tan(y) = (cos(x+y))/(sin(x)sin(y))
-
tan(x) + tan(y) = (cos(x-y))/(sin(x)sin(y))
A
Correct answer
Explanation
The sum-to-product identity for tangent is tan(x) + tan(y) = (sin(x+y))/(cos(x)cos(y)).
Which of the following is the difference-to-product identity for tangent?
-
tan(x) - tan(y) = (sin(x-y))/(cos(x)cos(y))
-
tan(x) - tan(y) = (sin(x+y))/(cos(x)cos(y))
-
tan(x) - tan(y) = (cos(x-y))/(sin(x)sin(y))
-
tan(x) - tan(y) = (cos(x+y))/(sin(x)sin(y))
A
Correct answer
Explanation
The difference-to-product identity for tangent is tan(x) - tan(y) = (sin(x-y))/(cos(x)cos(y)).
What is the half-angle identity for tangent?
-
tan(x/2) = (1 - cos(x))/(1 + cos(x))
-
tan(x/2) = (1 + cos(x))/(1 - cos(x))
-
tan(x/2) = (sin(x))/(cos(x))
-
tan(x/2) = (cos(x))/(sin(x))
A
Correct answer
Explanation
The half-angle identity for tangent is tan(x/2) = (1 - cos(x))/(1 + cos(x)).
Which of the following is the double-angle identity for tangent?
-
tan(2x) = (2tan(x))/(1 - tan^2(x))
-
tan(2x) = (2tan(x))/(1 + tan^2(x))
-
tan(2x) = (tan(x))/(1 - tan^2(x))
-
tan(2x) = (tan(x))/(1 + tan^2(x))
A
Correct answer
Explanation
The double-angle identity for tangent is tan(2x) = (2tan(x))/(1 - tan^2(x)).
Brahmagupta's formula for calculating the tangent of an angle is given by:
-
$\tan A = \frac{\sin A}{\cos A}$
-
$\tan A = \frac{\cos A}{\sin A}$
-
$\tan A = \frac{\sin A}{\sec A}$
-
$\tan A = \frac{\cos A}{\csc A}$
A
Correct answer
Explanation
Brahmagupta's formula for tangent is derived from the definition of tangent.
Brahmagupta's formula for calculating the tangent of the sum of two angles is given by:
-
$\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
-
$\tan(A + B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
-
$\tan(A + B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
-
$\tan(A + B) = \frac{\cos A + \cos B}{\sin A + \sin B}$
A
Correct answer
Explanation
Brahmagupta's formula for the tangent of the sum of two angles is derived from the angle addition formula for tangent.
Brahmagupta's formula for calculating the tangent of the difference of two angles is given by:
-
$\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
-
$\tan(A - B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
-
$\tan(A - B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
-
$\tan(A - B) = \frac{\cos A - \cos B}{\sin A - \sin B}$
A
Correct answer
Explanation
Brahmagupta's formula for the tangent of the difference of two angles is derived from the angle difference formula for tangent.