The value of $cos^2 10^o 15^o + cos^2 20^o +...... + cos^2 365^O$
Mathematics · Quantitative Aptitude
Trigonometric Identities and Values
74 QuestionsTrigonometric identities and values questions require evaluating complex angles using standard formulas. These are critical for quantitative aptitude sections in SSC and various state exams. Success depends on memorizing standard values and applying transformation rules.
Trigonometric Identities and Values Questions
$16 \cos^6 10^o - 24 \cos^4 10^o + 9 \cos^2 10^o$ is equal to
If $(1+\tan 1^{o})(1+\tan 2^{o})(1+\tan 3^{o})....(1+\tan 45^{o})=2^{n}$, then $n$ is equal to
Values of : $sin{ 10 }^{ 0 }sin{ 50 }^{ 0 }sin{ 60 }^{ 0 }sin{ 70 }^{ 0 }$ is
$sin^21^0+sin^22^0+sin^23^0+....+sin^290^0$
$\frac { cos{ 70 }^{ \circ } }{ sin{ 20 }^{ \circ } } +\frac { cos{ 59 }^{ \circ } }{ sin{ 31 }^{ \circ } } -8{ sin }^{ 2 }{ 30 }^{ \circ }$
The value of $(4 \, cos^2 9^o - 1) (4 cos^2 27^o - 1) (4 \, cos^2 81^o - 1) (4 \, cos^2 243^o - 1) $ is
$sin{ 40 }^{ \circ }{ 35 }^{ | }cos{ 19 }^{ \circ }{ 25 }^{ | }+cos{ 40 }^{ \circ }{ 35 }^{ | }sin{ 19 }^{ \circ }{ 25 }^{ |= }$
$\sqrt {3}\csc 20^{o}-\sec 20^{o}$ is equal to
Find the value of, $\dfrac {4}{3}\cot^{2}30^{o}+\cot^{2}60^{o}-2\csc ^{2}60^{o}-\dfrac {3}{4}\tan^{2}30^{o}$
$ \sqrt { 3 } \ cosec 20 ^ { \circ } - \sec 20 ^ { \circ }$ is equal to :
$Tan \,25^o.Tan \,31^o + Tan \,31^o.Tan \,34^o + Tan \,34^o .Tan \,25^o =$
Let $x=\sin 1^{o}$, then the value of expression
$\dfrac {1}{\cos 0^{o}\cos 1^{o}}+\dfrac {1}{\cos 1^{o}\cos 2^{o}}+\dfrac {1}{\cos 2^{o}\cos 3^{o}}+....+\dfrac {1}{\cos 44^{o}\cos 45^{o}}=$
$(1+\tan 5^{o})(1+\tan 10^{o})(1+\tan 15^{o}).....(1+\tan 45^{o})$ is equal to
$sin 12^o\sin\ 24^o\sin\ 48^o\sin\ 84^o$=