Quantitative Aptitude
Time, Speed and Distance
2,165 Questions
Time, Speed and Distance Questions
C
Correct answer
Explanation
100 miles/hour = 100 * 1.60934 km / 60 minutes = 160.934 / 60 km/min = 2.682 km/min. Rounding to one decimal place gives 2.7.
-
2.5 km
-
5 km
-
0.5 km
-
10 km
-
2.14 km
B
Correct answer
Explanation
Morning trip: 1 hour. Evening trip: 0.5 hours. Let D be distance and v be speed in morning. v = D/1. Evening speed = v + 5 = D/0.5 = 2D. So D/1 + 5 = 2D, which means D = 5 km.
-
20 km/hr
-
8.33 km/hr
-
12.5 km/hr
-
25 km/hr
-
16.66 km/hr
D
Correct answer
Explanation
Total distance = 60 + 40 + 50 = 150 km. Total time = (60/15) + (40/10) + (50/v) = 4 + 4 + 50/v = 8 + 50/v. Average speed = Total distance / Total time = 150 / (8 + 50/v) = 15. Solving: 150 = 15(8 + 50/v) => 10 = 8 + 50/v => 2 = 50/v => v = 25.
-
2.5 kmph
-
4.5 kmph
-
3.5 kmph
-
Cannot be determined
-
None of these
C
Correct answer
Explanation
Downstream speed = 10 km / 2 hr = 5 kmph. Downstream speed = boat speed + stream speed. 5 = boat speed + 1.5, so boat speed = 3.5 kmph.
-
45 km/hr
-
50 km/hr
-
60 km/hr
-
75 km/hr
-
80 km/hr
C
Correct answer
Explanation
Let original speed be v. 840/v - 840/(v+10) = 2. 420/v - 420/(v+10) = 1. 420(v+10-v) = v(v+10). 4200 = v^2 + 10v. v^2 + 10v - 4200 = 0. (v+70)(v-60) = 0. Since speed > 0, v = 60.
D
Correct answer
Explanation
Stopping distance is proportional to the square of the velocity (d proportional to v^2). If speed doubles (v becomes 2v), the distance becomes 2^2 = 4 times the original distance. Thus, 20 m * 4 = 80 m.
-
5 : 16
-
5 : 17
-
9 : 8
-
8 : 9
-
9 : 15
C
Correct answer
Explanation
The distance for each runner is not explicitly stated as equal, but in a relay, they cover the total distance. However, the question asks for the ratio of time taken by B and D. Time = Distance / Speed. Since they run the same distance (13.2 km / 4 = 3.3 km each), the ratio of time is (1/16) : (1/18) = 18 : 16 = 9 : 8.
-
90 kmph
-
105 kmph
-
150 kmph
-
120 kmph
D
Correct answer
Explanation
Let original speed be v and distance be d. Time taken is d/v. With snag, time is (d1/v) + (d2/(v/2)) = d/v + 45. If snag is 30km further, time is d/v + 30. Solving the system yields v = 120 kmph.
-
4 : 1
-
5 : 4
-
2 : 1
-
2 : 3
-
8 : 1
A
Correct answer
Explanation
Upstream speed = 10 - 6 = 4 m/s. Downstream speed = 10 + 6 = 16 m/s. Time is inversely proportional to speed. Ratio of times = 16 : 4 = 4 : 1.
-
78.26 km
-
75.41 km
-
70.20 km
-
65.39 km
B
Correct answer
Explanation
Time = 1 hr + 16/60 hr + 17/3600 hr = 1 + 0.2666 + 0.004722 = 1.271388 hr. Distance = 59.3 * 1.271388 = 75.39 km. Option B is the closest.
-
29.32 min
-
43.23 min
-
53.34 min
-
None of these
C
Correct answer
Explanation
Speed = 126 km/hr = 126 * (1000/60) m/min = 2100 m/min. Distance = 112.016 km = 112016 m. Time = 112016 / 2100 = 53.34 minutes.
-
445 km
-
444 km
-
440 km
-
425 km
-
None of these
B
Correct answer
Explanation
Let t be the time until they meet. Distance A = 16t, Distance B = 21t. Difference is 5t = 60, so t = 12 hours. Total distance = (16+21)*12 = 37*12 = 444 km.
-
0.5 km/hr
-
1.5 km/hr
-
1 km/hr
-
3 km/hr
A
Correct answer
Explanation
Upstream speed = 40/8 = 5 km/hr. Downstream speed = 36/6 = 6 km/hr. Stream speed = (Downstream - Upstream) / 2 = (6 - 5) / 2 = 0.5 km/hr.
C
Correct answer
Explanation
Original time = 5 hours, distance = 300 km. New time = 4/5 * 5 = 4 hours. New speed = distance / time = 300 / 4 = 75 km/hour.
-
223.23 km
-
228.2 km
-
231.58 km
-
308.2 km
C
Correct answer
Explanation
The planes travel at 22 kmph and 29 kmph for 5 hours, covering 110 km and 145 km. The angle between 350 degrees and 220 degrees is 130 degrees. Using the law of cosines: d^2 = 110^2 + 145^2 - 2 * 110 * 145 * cos(130). d = sqrt(12100 + 21025 - 31900 * (-0.6427)) = sqrt(33125 + 20502) = sqrt(53627) = 231.575 km.