Statistics Questions

Multiple choice
  1. 2.64

  2. 1.5

  3. 5.7

  4. 2.5

  5. NA

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Class intervals: 0-3, 3-6, 6-9, 9-12. Midpoints (x): 1.5, 4.5, 7.5, 10.5. Frequencies (f): 2, 4, 2, 2. Total N = 10. Mean = (1.5*2 + 4.5*4 + 7.5*2 + 10.5*2) / 10 = (3 + 18 + 15 + 21) / 10 = 5.7. Mean deviation = Sum(f * |x - mean|) / N = (2*|1.5-5.7| + 4*|4.5-5.7| + 2*|7.5-5.7| + 2*|10.5-5.7|) / 10 = (2*4.2 + 4*1.2 + 2*1.8 + 2*4.8) / 10 = (8.4 + 4.8 + 3.6 + 9.6) / 10 = 26.4 / 10 = 2.64.

Multiple choice
  1. 1.5

  2. -1.5

  3. 2

  4. -2.5

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Sum of deviations from A is sum(x_i - A) = sum(x_i) - nA. For A=50, sum(x_i) - 50n = -10. For A=46, sum(x_i) - 46n = 70. Subtracting equations: 4n = 80, so n = 20. Then sum(x_i) = 990. Mean = 990/20 = 49.5. Deviation from 48 = 49.5 - 48 = 1.5.

Multiple choice
  1. 28

  2. 44

  3. 36

  4. 18

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the numbers be x1, x2, x3, x4, x5. Let S = x1+x2+x3+x4+x5. The given values are (S-xi)/4 + xi = 41, 44, 50, 56, 65. This simplifies to S + 3xi = 164, 176, 200, 224, 260. Summing these: 5S + 3S = 1024, so 8S = 1024, S = 128. 3xi = 164-128=36 => xi=12; 176-128=48 => xi=16; 200-128=72 => xi=24; 224-128=96 => xi=32; 260-128=132 => xi=44.

Multiple choice
  1. 30

  2. 40

  3. 48

  4. 52

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let A = 2, then C = 3 (since 2 is 2/3 of 3). B is 20% more than A, so B = 2 * 1.2 = 2.4. Total of A and C is 2 + 3 = 5. B is 2.4, which is 2.6 less than 5. The percentage x is (2.6 / 5) * 100 = 52%.