Simple and Compound Interest Questions

Multiple choice
  1. 1500

  2. 750

  3. 650

  4. 875

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

SI = (P × R × T) / 100 = (5600 × 12.5 × 1.25) / 100 = 5600 × 0.125 × 1.25 = 700 × 1.25 = 875. Note that 15 months = 1.25 years, not 1.15 years. Option A (1500) would result from incorrectly using 15 years instead of 1.25 years.

Multiple choice
  1. 24.75

  2. 28

  3. 30

  4. 32.5

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let principal be P and rate be r%. In simple interest, amount = P(1 + rt/100). In 14 years, amount = 8P, so P(1 + 14r/100) = 8P. This gives 14r/100 = 7, so r = 50%. To become 16 times: P(1 + 50t/100) = 16P, so t/2 = 15, giving t = 30 years.

Multiple choice
  1. Rs.8000

  2. Rs.7850

  3. Rs.8192

  4. Rs.10000

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The difference between CI and SI for n years is P[(1 + r/100)^n - 1 - nr/100]. For n=3 at 12.5%, this is P[(1.125)^3 - 1 - 0.375] = P[0.0488]. For n=4, it is P[(1.125)^4 - 1 - 0.5] = P[0.1018]. The difference is P[0.052979] = 434, so P = 8192.

Multiple choice
  1. 60:41

  2. 41:60

  3. 51:60

  4. 60:51

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

SI for 2 years = 2000, so SI for 1 year = 1000. This means interest = 1000 annually. Principal P such that P × R × 2/100 = 2000. CI for 2 years is given as 2050. Using the CI formula and solving, we get CI for 2 years = 2050 and SI for 3 years = 3000. The ratio is 2050:3000 = 41:60.

Multiple choice
  1. 18000

  2. 17500

  3. 20000

  4. 24700

  5. 25600

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Annual compounding: Amount = P(1.2)² = 1.44P. Half-yearly: Rate = 10% per half-year, Amount = P(1.1)⁴ = 1.4641P. Difference = P(1.4641 - 1.44) = 0.0241P = 482. Therefore P = 482/0.0241 ≈ 20000. The key insight is that more frequent compounding yields higher returns.

Multiple choice
  1. Only I

  2. Only II

  3. Both I and II

  4. Either I or II

  5. Neither I nor II

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Statement I: Sum doubles in 12.5 years at simple interest, so rate = 100/12.5 = 8% per annum. Statement II: 5000 becomes 5832 in 2 years at CI. Using formula 5832 = 5000(1 + r/100)², we get r = 8% per annum. Either statement alone gives rate = 8%.

Multiple choice
  1. 7%

  2. 3%

  3. 5%

  4. 2%

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let P be the principal and r be the rate percent. SI for 2 years = P × r × 2/100 = 70, so Pr/50 = 70. CI for 2 years = P(1 + r/100)² - P = 70.70. Expanding: P(1 + 2r/100 + r²/10000) - P = 70.70, so 2Pr/100 + Pr²/10000 = 70.70. Substituting Pr = 3500: 2(3500)/100 + 3500r/10000 = 70.70, giving 70 + 0.35r = 70.70, so 0.35r = 0.70 and r = 2%.

Multiple choice
  1. Rs.6120

  2. Rs.6240

  3. Rs.6210

  4. Rs.6360

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Using the compound interest formula A = P(1 + r/100)^n: For P=25000, r=12%, n=2 years. Year 1: 25000 × 1.12 = 28000. Year 2: 28000 × 1.12 = 31360. Compound Interest = 31360 - 25000 = 6360. This can also be calculated directly: CI = P[(1 + r/100)^n - 1] = 25000[(1.12)^2 - 1] = 25000(1.2544 - 1) = 25000 × 0.2544 = 6360.

Multiple choice
  1. 3400

  2. 3200

  3. 3300

  4. 3000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Compound interest for 3 years minus compound interest for 2 years gives the interest earned in year 3 only. For 16% rate, amount after 2 years = P(1.16)², after 3 years = P(1.16)³. The difference is P(1.16)³ - P(1.16)² = P(1.16)²(0.16) = 15000 × 1.3456 × 0.16 = 3200 rupees approximately. Alternatively, this is the simple interest on the amount after 2 years for one more year at 16%.

Multiple choice
  1. 4%

  2. 5%

  3. 6%

  4. 8%

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The difference between compound interest and simple interest for 2 years is the interest on the first year's interest. CI - SI = Rs. 4100 - Rs. 4000 = Rs. 100. This Rs. 100 is the interest on the first year's simple interest. So if first year SI = Rs. 2000 (half of Rs. 4000), then Rs. 100 is interest on Rs. 2000 for 1 year. Therefore Rate = (100/2000) × 100 = 5%.

Multiple choice
  1. 3400

  2. 4400

  3. 3000

  4. 2000

  5. 6000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let P's investment be x. CI for 2 years at 20% = x×(1.2²-1) = x×0.44 = 0.44x. Q's investment is x-1600. SI for 3 years at 10% = (x-1600)×0.3. Given: 0.44x = 2×0.3×(x-1600), so 0.44x = 0.6x - 960. Solving: 0.16x = 960, x = 6000. Q's investment = 6000-1600 = 4400. Option B is correct. Common mistake: using wrong CI formula or misinterpreting the relationship.

Multiple choice
  1. 3,25,000 , 1,25,000

  2. 2,00,000 , 2,50,000

  3. 1,50,000 , 3,00,000

  4. 2,20,000 , 2,30,000

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let elder son get x, younger get (450000-x). After interest: x(1+0.05×3) and (450000-x)(1+0.02×5) must be equal. Solving: 1.15x = 1.1(450000-x) → 2.25x = 495000 → x = 220000. Elder gets 2,20,000; younger gets 2,30,000. Option D is correct.

Multiple choice
  1. Rs. 1800

  2. Rs. 1500

  3. Rs. 1250

  4. Rs. 1200

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let principal = P, rate = x%. CI for 1st year = P × x/100. CI for 2nd year = P(1 + x/100) × x/100 = (P × x/100)(1 + x/100). Given: 2nd year CI is 110% of 1st year CI, so (1 + x/100) = 1.10, giving x = 10%. SI for 5 years = P × 10 × 5/100 = P/2. CI for 5 years = P(1.1^5 - 1) ≈ 0.61051P. Difference = 0.61051P - 0.5P = 0.11051P ≈ Rs. 12. So P ≈ Rs. 108.6. Wait, let me reconsider. The difference between CI for 2nd year and SI for 5th year: CI(2nd year) = P × 0.1 × 1.1 = 0.11P. SI for 5th year alone = P × 0.1 = 0.1P. Difference = 0.11P - 0.1P = 0.01P = 12. So P = Rs. 1200.

Multiple choice
  1. Rs.2580

  2. Rs.2400

  3. Rs.2529

  4. Rs.3600

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let P be the sum. SI1 = P × 4 × 8/12 × 100 = P × 32/1200. SI2 = P × 5 × 15/12 × 100 = P × 75/1200. Given SI2 - SI1 = 129, so P × (75-32)/1200 = 129, P × 43/1200 = 129, P = 129 × 1200/43 = 3600. The difference in interest rates and time periods must be carefully accounted for.

Multiple choice
  1. If only statement I is sufficient.

  2. If only statement II is sufficient.

  3. If either I or II is sufficient.

  4. If neither I nor II is sufficient.

  5. If both statements I and II are necessary.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

From the problem: P doubles in 5 years at simple interest. So 2P = P(1 + 5r), giving r = 20%. Statement I gives the same rate (20%). Statement II: 3P = P(1 + 10r) gives r = 20%. Both statements give the same information but NO principal amount can be determined since the relationship works for ANY principal P. Therefore neither statement alone is sufficient to find the principal value.