Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs. 450
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Rs. 400
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Rs. 600
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Rs. 650
C
Correct answer
Explanation
Let the amount lent at 10% be x. Then amount at 8% is (1000-x). Total interest = 0.08(1000-x) + 0.10x = 80 - 0.08x + 0.10x = 80 + 0.02x. Average rate = (80+0.02x)/1000 = 0.092, so 80+0.02x = 92, giving 0.02x = 12, x = 600. The 10% amount is Rs. 600.
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$Rs. 204.4$
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$Rs. 302.2$
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$Rs. 244.8$
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$Rs. 272.6$
C
Correct answer
Explanation
Using CI formula: A = P(1+r)^n = 3000(1+0.04)² = 3000×1.0816 = 3244.8. CI = 3244.8 - 3000 = Rs. 244.8. The compound interest is Rs. 244.8.
C
Correct answer
Explanation
In compound interest, the amount grows by the same factor each year. 9680 × (1+r/100) = 10648, so 1+r/100 = 10648/9680 = 1.1. This gives r/100 = 0.1, so r = 10%.
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Rs. 930
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Rs. 700
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Rs. 850
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Rs. 900
A
Correct answer
Explanation
First find time: Interest = Rs. 725 - Rs. 500 = Rs. 225. Time = (SI × 100) / (P × R) = (225 × 100) / (500 × 9) = 5 years. Now for Rs. 600 at 11% for 5 years: SI = (600 × 11 × 5) / 100 = Rs. 330. Amount = Rs. 600 + Rs. 330 = Rs. 930.
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Rs. 16050
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Rs. 14750
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Rs. 15000
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Rs. 15500
C
Correct answer
Explanation
For annual installments under simple interest, each installment earns interest for the remaining period. Let annual installment = x. Total value: x(1 + 2×0.05) + x(1 + 1×0.05) + x = x(1.1 + 1.05 + 1) = 3.15x. This equals 47250, so x = 47250/3.15 = 15000. Verification: First installment earns 10% interest (2 years), second earns 5% (1 year), third earns nothing: 15000×1.1 + 15000×1.05 + 15000 = 16500 + 15750 + 15000 = 47250. Option A (16050) would give total 50557.5.
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Rs. 39,500/-
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Rs. 42,500/-
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Rs. 41,900/-
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Rs. 43,000/-
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None of these
B
Correct answer
Explanation
Let principal be P. Total SI = P×4×3/100 + P×8×2/100 + P×9×2/100 = 12P/100 + 16P/100 + 18P/100 = 46P/100 = 19550. So P = 19550×100/46 = 42500. The calculation is straightforward: different rates apply to different time periods, and simple interest is calculated on the same principal throughout.
A
Correct answer
Explanation
Use compound interest formula: A = P(1 + r/100)^t. Here 795.07 = 640(1 + r/100)^3. Solving: (1 + r/100)^3 = 795.07/640 = 1.2423. Taking cube root: 1 + r/100 = 1.075. Therefore r = 7.5%. Verify: 640 × 1.075^3 = 640 × 1.2423 ≈ 795.07. Options C and D are close but don't yield the exact amount.
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Rs. 1261
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Rs. 1324
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Rs. 1285
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Rs. 1129
A
Correct answer
Explanation
For quarterly compounding, rate per quarter = 20%/4 = 5%, time = 9 months = 3 quarters. Using A = P(1 + r/100)^n: A = 8000(1.05)³ = 8000 × 1.1576 = 9261. Compound Interest = 9261 - 8000 = Rs. 1261.
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Rs. 1600
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Rs. 2400
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Rs. 1820
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Rs. 2000
D
Correct answer
Explanation
Difference between CI and SI for 3 years at 5% is P[(1.05)³ - 1 - 0.15] = P[1.1576 - 1.15] = P(0.0076). Given difference is Rs. 15.25, so P = 15.25/0.0076 ≈ Rs. 2000. The formula for difference is: CI - SI = P[(1 + r/100)³ - 1 - 3r/100].
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Only II and III
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Any two
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Only I and III
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Any one
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None of these
B
Correct answer
Explanation
We need to find the rate of interest per annum. Statement I: Amount after 2 years at CI is Rs 11025. Statement II: Amount after 2 years at SI is Rs 11000. Statement III: Principal is Rs 10000. Using I+III: 11025 = 10000(1 + r/100)^2, we can find r. Using II+III: 11000 = 10000 + 10000×r×2/100, giving r = 5%. Using I+II: The difference between CI and SI for 2 years on same principal gives the rate. Any two statements are sufficient to determine r.
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Rs. 4894.56
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Rs. 4800
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Rs. 4600
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Rs. 4884.64
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Rs. 4994.56
E
Correct answer
Explanation
Compound Interest formula: A = P(1 + r/100)^n. Here P=40000, r=4%, n=3. A = 40000(1.04)³ = 40000 × 1.124864 = 44994.56. Compound Interest = A - P = 44994.56 - 40000 = 4994.56. The answer is Rs. 4994.56.
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Rs. 82500
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Rs. 25000
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Rs. 72500
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Rs. 62500
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None of these
D
Correct answer
Explanation
For 3 years at 5%, CI - SI = P[(1+r/100)³ - 1 - 3r/100] = P[(1.05)³ - 1 - 0.15] = P[1.157625 - 1 - 0.15] = P(0.007625). Given this equals 190625, so P = 190625/0.007625 = 25000000. For 2 years: CI - SI = P[(1.05)² - 1 - 0.10] = 25000000[1.1025 - 1 - 0.10] = 25000000(0.0025) = 62500. Or use direct formula: Difference for n years = P(r/100)²(n-1)/2 for first 2 years, but the 3-year formula gives us P, then apply for 2 years.
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$Rs 1.20$
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$Rs 1.60$
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$Rs 2.40$
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$Rs 3.60$
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None of these
A
Correct answer
Explanation
Principal = Rs 10. Rate = 3 paise per rupee per annum = 3% per annum. Time = 4 months = 4/12 = 1/3 year. Simple Interest = P × R × T / 100 = 10 × 3 × (1/3) / 100 = 10 × 1 / 100 = Rs 0.10. Wait, this calculation gives Rs 0.10, not Rs 1.20. Let me recalculate: 3 paise per rupee means 3 paise on Rs 1 for the given period. If the rate is 3 paise per rupee for 4 months, then on Rs 10, the interest is 30 paise = Rs 0.30. But if the rate is 3 paise per rupee per annum, then for 4 months: SI = 10 × 3 × (1/3) / 100 = 0.10. Neither matches Rs 1.20. However, if the question means the rate is 3 paise per rupee per month (annualized to 36%), then SI = 10 × 36 × (1/3) / 100 = Rs 1.20. This interpretation gives option A.
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Rs 70433.5
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Rs 70200
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Rs 70933.5
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Rs 70633.5
D
Correct answer
Explanation
Compound Interest formula: A = P(1 + r/100)ⁿ. Principal = Rs 60,000, rate = 8.5%, time = 2 years. A = 60000 × (1 + 8.5/100)² = 60000 × (1.085)² = 60000 × 1.177225 = Rs 70633.5. The compound amount after 2 years is Rs 70633.5.
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Rs 4460
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Rs 4384
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Rs 4498
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Rs 4402
A
Correct answer
Explanation
Let P be principal. After 3 years: P(1+r)³ = 6690. After 6 years: P(1+r)⁶ = 10035. Dividing: (1+r)³ = 10035/6690 = 1.5. Substituting back: P × 1.5 = 6690, so P = 6690/1.5 = 4460.