Simple and Compound Interest Questions

Multiple choice
  1. 219.75%

  2. 217.95%

  3. 217.19%

  4. 216.31%

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice
  1. 9.75%

  2. 10.45%

  3. 11.52%

  4. 12.25%

  5. 13.75%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

CI = P(1+r/100)^2 - P. SI = P*R*2/100. CI = 1.5 * SI. P((1+0.16)^2 - 1) = 1.5 * (P*R*2/100). (1.16^2 - 1) = 0.03R. 1.3456 - 1 = 0.03R. 0.3456 = 0.03R. R = 11.52.

Multiple choice
  1. Rs. 751

  2. Rs. 795

  3. Rs. 1068

  4. Rs. 1120

  5. Rs. 2060

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Scheme 1: 10250 at 12% p.a. compounded quarterly (3% per quarter) for 4 quarters. Interest = 10250 * (1.03^4 - 1) = 10250 * 0.12550881 = 1286.46. Scheme 2: 12250 at 16% p.a. compounded quarterly (4% per quarter) for 4 quarters. Interest = 12250 * (1.04^4 - 1) = 12250 * 0.16985856 = 2080.77. Difference = 2080.77 - 1286.46 = 794.31, which rounds to 795.

Multiple choice
  1. 22.51%

  2. 26.56%

  3. 27.51%

  4. 28.15%

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Simple interest doubling in 8 years means rate = 100/8 = 12.5%. For compound interest over 2 years at 12.5%, the amount is P*(1.125)^2 = 1.265625*P. The return is 26.56%.

Multiple choice
  1. 17,080

  2. 15,669

  3. 13,189

  4. 14,376

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Compound interest for the 3rd year is P * (1+r)^2 * r. Given 12100 = P * (1.09)^2 * 0.09. The interest for the 4th year is P * (1+r)^3 * r. This is equivalent to (Interest for 3rd year) * (1+r) = 12100 * 1.09 = 13189.

Multiple choice
  1. 86,000

  2. 81,600

  3. 90,000

  4. 94,000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Since the principal increases by 8% in 2 years under simple interest, the annual interest rate is 4%. Applying this 4% annual rate to a principal of Rs. 10 lakh compounded annually for 2 years results in an effective interest of 8.16%. Calculating 8.16% of Rs. 10 lakh gives Rs. 81,600.

Multiple choice
  1. Rs. 10000

  2. Rs. 20000

  3. Rs. 18000

  4. Rs. 15000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let A borrow x, then B borrows 30000-x. Interest for A is (x*4*5)/100 = 0.2x. Interest for B is ((30000-x)*5*4)/100 = 0.2(30000-x). Given 0.2x = 2 * 0.2(30000-x), so x = 2(30000-x), 3x = 60000, x = 20000.

Multiple choice
  1. 250

  2. 300

  3. 280

  4. 270

  5. 290

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Compound interest for the 3rd year is the amount at the end of the 2nd year multiplied by the interest rate. If the 2nd year interest is 250, the principal for the 3rd year is the original principal plus the 1st year interest. However, a simpler way is to note that interest in year n+1 is (1+r) times interest in year n. Thus, 250 * 1.12 = 280.

Multiple choice
  1. Only I and II

  2. Only I and III

  3. Only II and either I or III

  4. All I, II and III

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

To find the sum (Principal P), we need the relationship between interest, rate, and time. Statement III provides the interest difference when the rate changes, which allows us to set up an equation: (P * (R+2) * 4)/100 - (P * R * 4)/100 = 56. This simplifies to 8P/100 = 56, allowing us to solve for P. All three statements are necessary to define the parameters.