Simple and Compound Interest Questions

Multiple choice
  1. Rs. 304

  2. Rs. 335

  3. Rs. 288

  4. Rs. 311

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let P be the principal. CI for 3rd year = P(1+r)^2 * r = 3600. So P(1.08)^2 * 0.08 = 3600 => P * 1.1664 * 0.08 = 3600 => P = 3600 / 0.093312 = 38579.8. CI 4th year = P(1.08)^3 * 0.08 = 38579.8 * 1.2597 * 0.08 = 3888. CI 5th year = P(1.08)^4 * 0.08 = 38579.8 * 1.3605 * 0.08 = 4199.04. Difference = 4199.04 - 3888 = 311.04.

Multiple choice
  1. 100(1.02)

  2. 200(1.02)

  3. 100(1.02)2

  4. 200(1.02)2

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Compound interest formula is A = P(1+r)^t. For 2 years, it is 200(1.02)^2. For 1 year, it is simply 200(1.02)^1, which is 200(1.02).

Multiple choice
  1. Rs. 320

  2. Rs. 620

  3. Rs. 900

  4. Rs. 800

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the annual deposit be x. The deposits earn simple interest for 5, 4, 3, 2, 1, and 0 years respectively. The total amount is 6x + x * 0.12 * (5+4+3+2+1) = 6x + 0.12 * 15x = 6x + 1.8x = 7.8x. Setting 7.8x = 6240 gives x = 800.

Multiple choice
  1. Rs. 10,000

  2. Rs. 11,000

  3. Rs. 12,000

  4. Rs. 10,800

  5. Rs. 5,000

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Fund-1: M * (1.2^2 - 1) = 7150 => M * 0.44 = 7150 => M = 16250. Fund-2: Principal = 16250 + 3750 = 20000. Interest = (20000 * 12.5 * 4) / 100 = 20000 * 0.5 = 10000.