Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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3 years
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4 years
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5 years
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6 years
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7 years
A
Correct answer
Explanation
Interest earned = 22125 - 18750 = 3375. Using I = P * r * t / 100, we get 3375 = 18750 * 6 * t / 100. Solving for t: 3375 = 1125 * t, so t = 3.
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Rs. 10
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Rs. 5
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Rs. 12
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Rs. 15
B
Correct answer
Explanation
Difference = P * (r/100)^2 = 500 * (10/100)^2 = 500 * 0.01 = 5.
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Rs. 2100
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Rs. 1900
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Rs. 2000
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Rs. 2200
C
Correct answer
Explanation
Compound Interest formula: A = P(1 + r/100)^n. CI = P((1 + 0.1)^3 - 1) = 662. P(1.331 - 1) = 662. P(0.331) = 662. P = 662 / 0.331 = 2000.
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Rs. 14,790
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Rs. 390
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Rs. 4680
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Rs. 780
B
Correct answer
Explanation
For a recurring deposit of Rs. 1200 per month for 1 year at 5% simple interest, the interest is calculated on the sum of monthly balances. The total principal is 1200*12 = 14400. The equivalent principal for one month is 1200 * (12*13/2) = 93600. Interest = (P * R * T) / 100 = (93600 * 5 * 1) / (100 * 12) = 390.
B
Correct answer
Explanation
Effective rate = (1 + r/n)^n - 1. Here r = 0.10, n = 2. (1 + 0.05)^2 - 1 = 1.1025 - 1 = 0.1025 = 10.25%.
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Rs. 3,25,491
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Rs. 3,25,941
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Rs. 3,24,480
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Rs. 3,23,490
C
Correct answer
Explanation
Original bill = 5000. Y pays 1/5 = 1000. Balance = 4000. Interest on 4000 for 3 months at 12% = 4000 * 0.12 * (3/12) = 120. New bill = 4000 + 120 = 4120.
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Rs. 6200
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Rs. 5400
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Rs. 5200
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Rs. 5600
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Rs. 4800
C
Correct answer
Explanation
Let the amount be P. Interest A pays B = P * 0.1 * 3 = 0.3P. Interest B receives from C = P * 0.2 * 3 = 0.6P. B's income = 0.6P - 0.3P = 0.3P. Given 0.3P = 1560, P = 1560 / 0.3 = 5200.
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Rs. 16,910
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Rs. 12,800
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Rs. 12,960
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Rs. 11,960
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None of these
D
Correct answer
Explanation
CI = 91000 * (1.2^2 - 1) = 91000 * 0.44 = 40040. SI = 91000 * (100/7)/100 * 4 = 91000 * (1/7) * 4 = 52000. The difference is 52000 - 40040 = 11960.
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4 : 5
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3 : 5
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5 : 4
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2 : 1
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None of these
A
Correct answer
Explanation
Let the interest rates be 10k and 8k, and the amounts deposited be P1 and P2. For equal interest, P1 * 10k = P2 * 8k, which simplifies to P1/P2 = 8/10 = 4/5.
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3 Years
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4 Years
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5 years
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6 years
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Cannot be determined
C
Correct answer
Explanation
Let x be the number of years before the scheme was introduced. The interest for the first x years is (10000 * 7 * x) / 100 = 700x. For the remaining (10-x) years, the rate is 5%, so interest is (10000 * 5 * (10-x)) / 100 = 500(10-x). Total amount = Principal + Interest = 10000 + 700x + 5000 - 500x = 16000. Solving 15000 + 200x = 16000 gives 200x = 1000, so x = 5.
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Rs. 169198
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RS. 169918
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Rs. 196918
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Rs. 199698
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None
A
Correct answer
Explanation
Interest each year = 124000 * 0.05 = 6200. Tax = 19% of 6200 = 1178. Net interest = 6200 - 1178 = 5022. Total amount after 9 years = 124000 + (9 * 5022) = 124000 + 45198 = 169198.
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Rs. 6855.63
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Rs. 6850.63
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Rs. 6859
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Rs. 6871
A
Correct answer
Explanation
The amount to be financed is 25000 - 5000 = 20000. Using the annuity formula P = A * P(n, i), where P is the principal, A is the annual payment, and P(4, 0.14) is the present value factor, A = 20000 / 2.91731 = 6855.63.
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Rs. 30,000
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Rs. 33,000
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Rs. 40,000
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Rs. 45,000
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None of these
A
Correct answer
Explanation
Amount after 2 years CI = x(1.05)^2 = 1.1025x. Interest on this for 2 years SI at 20% = 1.1025x * 0.2 * 2 = 0.441x. Total = 1.1025x + 0.441x = 1.5435x = 46305. x = 30000.
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Rs. 10,500
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Rs. 10, 250
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Rs. 10,000
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Rs. 9,500
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None of these
C
Correct answer
Explanation
Simple interest for 4 years (7-3) is 13500 - 11500 = 2000. Interest per year = 500. Interest for 3 years = 1500. Principal = 11500 - 1500 = 10000.