Simple and Compound Interest Questions

Multiple choice
  1. -4.5%

  2. +3.5%

  3. -4.32%

  4. +5.5%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Initial assets: 90,000. Spent: 15k+13k+35k = 63k. Remaining: 27k. Bank deposit after 2 years: 27000 * (1.15)^2 = 27000 * 1.3225 = 35707.5. Sale of items: 80% of 63k = 50400. Total final assets = 35707.5 + 50400 = 86107.5. Change = 86107.5 - 90000 = -3892.5. Percentage change = (-3892.5 / 90000) * 100 = -4.325%.

Multiple choice
  1. Rs 2400

  2. Rs 1800

  3. Rs 2000

  4. Rs 2500

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the instalments be x, 2x, and 3x. The present value of these instalments at 10% interest is x/1.1 + 2x/(1.1^2) + 3x/(1.1^3) = 12820. Solving this equation yields x = 2000.

Multiple choice
  1. Scheme 2 is better by 15% percent

  2. Scheme 1 is better by 15% percent

  3. Scheme 1 is better by 20% percent

  4. Scheme 2 is better by 20% percent

  5. Both schemes give same amount

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Scheme 1: SI = 50% * 1.5 = 75%. Scheme 2: CI at 25% per half-year for 3 periods. Amount = P(1 + 0.25)^3 = P(1.25)^3 = P(1.953125). Interest = 95.3125%. Difference = 95.31 - 75 = 20.31%. Approximately 20%.

Multiple choice
  1. A. 12000

  2. 12500

  3. 10000

  4. 10500

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let P be the sum. Amount after 17 years = P * (1 + 0.07*11 + 0.08*6) = P * (1 + 0.77 + 0.48) = 2.25P. Compound interest on 2.25P for 2 years at 12% is 2.25P * ((1.12)^2 - 1) = 2.25P * 0.2544 = 0.5724P. Setting 0.5724P = 5724 gives P = 10000.

Multiple choice
  1. Rs.600

  2. Rs.800

  3. Rs.650

  4. Data Insufficient

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Simple interest SI = P*R*T/100. Changes in P and T provide equations, but there are three variables (P, R, T) and only two equations. Thus, the original principal, rate, and time cannot be uniquely determined.

Multiple choice
  1. Rs. 20300

  2. Rs. 20401

  3. Rs. 20554

  4. Rs.20612

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the first payment be x and the second be 2x. The total amount is 56440. The interest is applied to the balance after the first payment. Solving the equation x + 2x(1 + 0.05)^-1 = 56440 leads to the result.

Multiple choice
  1. Rs.6600

  2. Rs.6550

  3. Rs.6450

  4. Rs.6615

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let amounts be P1 and P2. P1(1.05)^9 = P2(1.05)^11. P1 = P2(1.05)^2 = P2(1.1025). P1 + P2 = 12615. 2.1025*P2 = 12615. P2 = 6000. P1 = 12615 - 6000 = 6615.