Simple and Compound Interest Questions

Multiple choice
  1. 12.5%

  2. 12%

  3. 15%

  4. 18%

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let principal be P and rate be R%. Simple interest for 3 years: 3PR/100 = 7200, so PR = 240000. Compound interest for 2 years: P[(1 + R/100)² - 1] = 5160. Substituting P = 240000/R: (240000/R)[(1 + R/100)² - 1] = 5160. Testing R = 15%: (240000/15)[1.3225 - 1] = 16000 × 0.3225 = 5160. This matches exactly.

Multiple choice
  1. 7784.24

  2. 7854.5

  3. 7896.24

  4. 7902.72

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let principal be P. CI in 3rd year = P(1.12)³ - P(1.12)² = P × 1.12² × 0.12 = 7056. So P × 1.2544 × 0.12 = 7056, giving P = 7056/0.150528 = 49000 (approx). CI in 4th year = P(1.12)⁴ - P(1.12)³ = P × 1.12³ × 0.12 = 49000 × 1.404928 × 0.12 = 7902.72.

Multiple choice
  1. 27000

  2. 25000

  3. 28000

  4. 22000

  5. 26000

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let amount in scheme B be x, so scheme A is 35000-x. Interest: 0.12x + 0.05(35000-x) = 3500. Solving: 0.12x + 1750 - 0.05x = 3500, so 0.07x = 1750, giving x = 25000. Pawan invested Rs. 25000 in scheme B at 12% to earn the desired total interest.

Multiple choice
  1. 1352

  2. 1377

  3. 1275

  4. 1283

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For compound interest with equal yearly instalments, let each instalment be x. After 1 year, amount is 2550(1.04). Pay x, balance is 2550(1.04) - x. After 2nd year, this becomes (2550(1.04) - x)(1.04). This equals x. Solving: 2550(1.04²) - x(1.04) = x, so x = 2550(1.0816)/2.04 ≈ 1352. Each instalment is approximately Rs. 1352.

Multiple choice
  1. 20000

  2. 16000

  3. 15680

  4. 24580

  5. 22650

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let sum be P. After 2 years at 12% SI: amount = P(1 + 0.12×2) = 1.24P. This is invested at 10% CI for 2 years: maturity = 1.24P(1.1)² = 1.24P × 1.21 = 1.5004P. Interest = 1.5004P - 1.24P = 0.2604P = 5208. So P = 5208/0.2604 = 20000. The key is tracking principal through both investment stages.

Multiple choice
  1. 2000

  2. 1800

  3. 300

  4. 1500

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the sum be P and time be t years. SI = P/4 = (P × r × t)/100 gives rt = 25. Given r = 4t, we get 4t² = 25, so t = 2.5 years and r = 10%. New rate = 12%, so SI on ₹5000 for 3 years = (5000 × 12 × 3)/100 = ₹1800.

Multiple choice
  1. 119880

  2. 119650

  3. 119885

  4. 119841

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

When interest is compounded every 9 months, the annual rate of 20% converts to 15% per period (20% × 9/12). In 3 years, there are 4 compounding periods. Amount = 160000(1.15)^4 ≈ 279841, so CI ≈ 119841. If 20% per 9-month period were used, CI would be ~171776, which matches no option.

Multiple choice
  1. 14%

  2. 15%

  3. 20%

  4. 10%

  5. None of these. इनमे से कोई नहीं

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For compound interest, amount increases by (1 + r) each year. A₈/A₇ = 1344/1200 = 1.12. Therefore 1 + r = 1.12, so r = 0.12 = 12%. Rate is 12%, not in options A-D.

Multiple choice
  1. 5000

  2. 8000

  3. 6500

  4. cannot be determined

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let amounts in A, B, C be x, y, z respectively. Given z = 150% of x = 1.5x and z = 240% of y = 2.4y. From interest equation: 0.1x + 0.12y + 0.15z = 3200. Substituting x = 2z/3 and y = 5z/12 gives 0.1(2z/3) + 0.12(5z/12) + 0.15z = 3200. Solving yields z = 12000, so y = 5/12 × 12000 = 5000. Option A is correct.

Multiple choice
  1. 12000

  2. 14000

  3. 16000

  4. 12500

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let A=100x, then C=140% of A=140x. Also C=175% of B, so 140x=1.75B, B=80x. Interest: 8% of A + 10% of B + 12% of C = 6560. 8x + 8x + 16.8x = 6560. 32.8x=6560, x=200. B=80x=16000. Check: A=20000 (8%=1600), B=16000 (10%=1600), C=28000 (12%=3360). Total interest = 1600+1600+3360=6560. ✓