Physics
Rotational and Circular Motion
235 Questions
Rotational and circular motion examines the dynamics of objects moving in circular paths or rotating around an axis. Key concepts include angular momentum, torque, moment of inertia, and centripetal force. This is a highly scoring topic in the physics section of competitive exams.
Angular momentumCentripetal forceMoment of inertiaRolling objectsGyroscopic effect
Rotational and Circular Motion Questions
A spinning top is slowing down due to friction. What happens to its angular momentum?
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It increases
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It remains the same
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It decreases
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It becomes zero
C
Correct answer
Explanation
As the spinning top slows down, its angular momentum decreases due to the frictional force.
What is the angular momentum of a rigid body rotating about a fixed axis with angular velocity (\omega) and moment of inertia (I)?
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\(I\omega\)
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\(\frac{1}{2}I\omega^2\)
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\(2I\omega\)
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\(\frac{1}{2}I\omega\)
A
Correct answer
Explanation
The angular momentum of a rigid body rotating about a fixed axis is given by (I\omega).
What is the kinetic energy of a rigid body rotating about a fixed axis with angular velocity (\omega) and moment of inertia (I)?
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\(\frac{1}{2}I\omega^2\)
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\(I\omega\)
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\(2I\omega^2\)
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\(\frac{1}{2}I\omega\)
A
Correct answer
Explanation
The kinetic energy of a rigid body rotating about a fixed axis is given by (\frac{1}{2}I\omega^2).
What is the torque acting on a rigid body rotating about a fixed axis with angular acceleration (\alpha) and moment of inertia (I)?
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\(I\alpha\)
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\(\frac{1}{2}I\alpha^2\)
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\(2I\alpha\)
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\(\frac{1}{2}I\alpha\)
A
Correct answer
Explanation
The torque acting on a rigid body rotating about a fixed axis is given by (I\alpha).
What is the equation of motion for a rigid body rotating about a fixed axis?
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\(I\alpha = \sum\tau\)
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\(\frac{1}{2}I\alpha^2 = \sum\tau\)
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\(2I\alpha = \sum\tau\)
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\(\frac{1}{2}I\alpha = \sum\tau\)
A
Correct answer
Explanation
The equation of motion for a rigid body rotating about a fixed axis is (I\alpha = \sum\tau).
What is the angular velocity of a rigid body rotating about a fixed axis with constant angular acceleration (\alpha) and initial angular velocity (\omega_0) after time (t)?
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\(\omega_0 + \alpha t\)
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\(\omega_0 - \alpha t\)
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\(2\omega_0 + \alpha t\)
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\(\frac{1}{2}\omega_0 + \alpha t\)
A
Correct answer
Explanation
The angular velocity of a rigid body rotating about a fixed axis with constant angular acceleration (\alpha) and initial angular velocity (\omega_0) after time (t) is given by (\omega_0 + \alpha t).
What is the angular displacement of a rigid body rotating about a fixed axis with constant angular acceleration (\alpha) and initial angular velocity (\omega_0) after time (t)?
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\(\omega_0 t + \frac{1}{2}\alpha t^2\)
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\(\omega_0 t - \frac{1}{2}\alpha t^2\)
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\(2\omega_0 t + \alpha t^2\)
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\(\frac{1}{2}\omega_0 t + \alpha t^2\)
A
Correct answer
Explanation
The angular displacement of a rigid body rotating about a fixed axis with constant angular acceleration (\alpha) and initial angular velocity (\omega_0) after time (t) is given by (\omega_0 t + \frac{1}{2}\alpha t^2).
What is the relationship between the linear velocity (v) of a point on a rigid body rotating about a fixed axis and the angular velocity (\omega) of the body?
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\(v = \omega r\)
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\(v = \frac{1}{2}\omega r\)
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\(v = 2\omega r\)
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\(v = \frac{1}{4}\omega r\)
A
Correct answer
Explanation
The relationship between the linear velocity (v) of a point on a rigid body rotating about a fixed axis and the angular velocity (\omega) of the body is given by (v = \omega r), where (r) is the distance from the point to the axis of rotation.
What is the relationship between the centripetal acceleration (a_c) of a point on a rigid body rotating about a fixed axis and the angular velocity (\omega) of the body?
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\(a_c = \omega^2 r\)
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\(a_c = \frac{1}{2}\omega^2 r\)
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\(a_c = 2\omega^2 r\)
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\(a_c = \frac{1}{4}\omega^2 r\)
A
Correct answer
Explanation
The relationship between the centripetal acceleration (a_c) of a point on a rigid body rotating about a fixed axis and the angular velocity (\omega) of the body is given by (a_c = \omega^2 r), where (r) is the distance from the point to the axis of rotation.
What is the center of mass of a uniform rod?
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The midpoint of the rod
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One-third of the way from one end of the rod to the other
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Two-thirds of the way from one end of the rod to the other
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The end of the rod
A
Correct answer
Explanation
The center of mass of a uniform rod is the midpoint of the rod. This is because the mass of the rod is evenly distributed along its length.