Programming Output Evaluation

This is the correct option as the variable alpha is initialized with the value 65, which is an ASCII equivalent of 'A'. Since, 'for' loop lasts for the values 0 and 1, therefore the values 65 and 66 are initialized to the char array 'ch' that is nothing but ASCII value of 'A' and 'B'.

This is the correct option as the value of n = - 10 is already assigned, and m = - ( - n) + 5 will give the resultant value 15.

This is the correct option as the ASCII value of 'a' is 97 and 'A' is 65, and their difference is 32.

This is the correct option as floor() function returns the smallest integer value to the assigned value.

This is the correct option as initial value of a is 3, and after addition with b, results in 5.

This conversion character is used to display strings in the output statement.

This option is correct because when the compiler prints 'I am the best' for the very first time, it subsequently reads exit() and the program execution comes to an end. Hence, the statement will be printed only once.

This is the correct option as the contents of pointer is incremented by 1 to store 'd'.

This is the correct option as bitwise AND operator, when operated on binary 0101 and 0010 results in 0000.

This is the correct answer. Substring method takes two parameters (beginIndex,EndIndex).Substring( int Begin , int End). It return the string from begin to end – 1.But if the begin index is greater than the endindex, then a "IndexOutOfBoubd" exception will occur. So here substring(4,3) will give runtime error.So this is the correct answer.

This is the correct answer. The compiler will throw an error that method match() was not declared.Because String class do not contains any method named match().The correct method is matches(). So the above statement should be s.matches(s1).So this is the correct answer.

This is the correct answer. S.length() wil return 15 because there are 15 characters in the String.So the code looks like this :-s.charAt(15);the index count starts at 0. In this way the last character a is at index number 14. So if we try to access a character in a string which is out of bound then a runtime exception “StringOutOfBound” will be thrown.So we can pass only till s.charAt(s.length()-1).So this is correct answer.

This is the correct answer. delete(int start , int end) delete the characters from the start index till end-1 index.So the welcome to java will delete the characters from 8 to 11 characters.So the resulting string remains “ Welcome ava”.Index starts from 0.So this is the correct answer.

This is the correct answer. Length() function return the number of characters in the string. As we can count that the number of characters in the given string are 15. So length() will return 15.charAt() function return the character at the given index in the parameter. Remember that the index count starts at 0.So charAt(0) is W , counting in this way we reach charAt(9) is o.So this is the correct answer.

This is the correct answer. Substring method takes two parameters (beginIndex,EndIndex).Substring( int Begin , int End). It return the string from begin to end – 1.But if the begin index is equal to the endindex then an empty String with length 0 will be returned. So here substring(4,4) will return an empty string of length 0.So this is the correct answer.