Programming Output Evaluation

Case 2 is given two times.

Standard output is typically line-buffered or fully buffered. If the program crashes before a newline is encountered or the buffer is flushed, the output may not appear.

The array initialization contains 6 strings separated by commas: 'Sleepy', 'Dopey Doc', 'Happy', 'Grumpy Sneezy', 'Bashful'. Wait, the list is: Sleepy, Dopey Doc, Happy, Grumpy Sneezy, Bashful. That is 5 elements.

The pointer ptr is incremented by 5, so it points to the character '5'. Printing ptr prints '56789'. Printing buffer prints the entire string '0123456789'.

The ternary operator (L==B) ? 1 : 0 checks if L equals B. Since both are assigned 2, the condition is true, resulting in the value 1.

The do-while loop executes at least once. Inside, index becomes 8 and sum becomes 2. The condition (index > 9) is checked, which is (8 > 9), so the loop terminates.

The loop runs for digit 0 to 9. After the loop finishes, the variable digit is 10. Then digit = 2 * 10 = 20, and finally --digit results in 19.

The sqrt function expects a double argument. Casting the integer i to double ensures the correct function overload or conversion is used.

b=2. a = 2 * (b++) uses the current value of b (2) then increments b to 3. So a = 4. Then c = 2 * (++b) increments b to 4 then uses it, so c = 2 * 4 = 8.

y starts at 10. (y++ > 9) is true (10 > 9), y becomes 11. (y++ != 10) is true (11 != 10), y becomes 12. (y++ > 10) is true (12 > 10), y becomes 13. All conditions true, y ends at 13.

The printf function takes a format string as the first argument. Subsequent arguments are ignored if there are no format specifiers in the string.

The expression a+++++b is parsed as (a++) + (++b). a is 5, b is 2. (5++) + (++2) = 5 + 3 = 8. Since 8 is not an option, the answer is none of the above.

In C, the name of a function used in an expression decays to a pointer to that function, which is its starting address.