Here we have set basefield flag as hex which will display100 in hex and output is 64. Hence, the given option is correct.

The basic thing that we need to remember in C is that zero means false. Now, the code inside for loop as condition is checked. Variable i is zero since we are using post-increment operator. Hence, loop is terminated and after that 1 is printed which is the final value of i. Therefore, this is the correct answer. 

When expressions are seperated by comma operator, they are evaluated from left and the rightmost expressions only used for assignment. Hence, 5 is assigned to a and 5 is printed on the screen. This is the correct answer.

As shown in the code, i is incremented two times. In first cout, 1 will be displayed and in second cout -since a is incremented twice by then, 3 is displayed. Hence, 1 3 is the correct output.

Initially, a[1] is 1. The line i = ++a[1] increments a[1] to 2 and sets i to 2. Then j = a[1]++ sets j to 2 and increments a[1] to 3. Finally, m = a[i++] assigns a[2](which is 15) to m and increments i to 3, resulting in 3 2 15.

DIM1 is a macro that calculates the array size correctly (10) because the array name in that scope represents the whole array. In DIM2, the array decays into a pointer when passed as an argument, so sizeof(array) returns the size of a pointer, resulting in 1.

In many C compilers, printf arguments are evaluated from right to left. Starting from the right, ++j makes j=3, then j is 3, then i++ returns 2 (and i becomes 3), and finally i is 3, resulting in the output 3 2 3 3.

The extern keyword tells the compiler that the variable 'out' is defined elsewhere. Even though the actual definition of 'out' appears after the main function, the linker will correctly resolve the reference to the global variable and print 100.

The goto statement in C is restricted to jumping within the same function. Because the label 'here' is defined in fun() and the goto statement is in main(), the code will fail to compile.

The expression *a + 1 - *a + 3 simplifies mathematically because the terms *a and -*a cancel each other out. This leaves 1 + 3, which results in 4, regardless of the values stored in the array.

The string 'Angel' is stored with a null terminator at index 5. Modifying the character at index 6 does not affect the null terminator at index 5, so printf stops at the end of 'Angel'.

The scanf function returns the number of items successfully read and assigned. Since one integer is successfully scanned into variable i, scanf returns 1, which is then printed by the outer printf.

In a 16-bit system, -1 is represented as 0xFFFF in two's complement. Shifting this value left by 4 bits results in 0xFFF0, which is printed as fff0 by the %x format specifier.

The expression sizeof(*p) gives the size of a char (1 byte), while sizeof(p) gives the size of the pointer itself. In many 16-bit environments, pointers are 2 bytes, leading to the output 1 2.