Quantitative Aptitude
Pipes and Cisterns
535 Questions
Pipes and Cisterns Questions
-
2520 litres
-
3760 litres
-
2836 litres
-
2250 litres
A
Correct answer
Explanation
Leak rate = 1/7 tank/hr. Let inlet rate be I. Net rate = I - 1/7 = -1/10.5 = -1/(21/2) = -2/21. I = 1/7 - 2/21 = 3/21 - 2/21 = 1/21. Inlet fills 1/21 tank per hour. Inlet rate = 2 L/min = 120 L/hr. 1/21 capacity = 120 L, so capacity = 120 * 21 = 2520 litres.
-
20 minutes
-
24 minutes
-
36 minutes
-
48 minutes
-
54 minutes
D
Correct answer
Explanation
Work rates: A = 1/12, B = 1/16, C = -1/8. Combined rate = 1/12 + 1/16 - 1/8 = (4 + 3 - 6) / 48 = 1/48. The cistern fills in 48 minutes.
-
167 minutes
-
160 minutes
-
157 minutes
-
155 minutes
-
172 minutes
A
Correct answer
Explanation
A fills 1/20, B fills 1/30, C empties 1/15. Net rate per 3 minutes = 1/20 + 1/30 - 1/15 = 3/60 + 2/60 - 4/60 = 1/60. The tank fills 1/60 every 3 minutes. To avoid overfilling, consider the last cycle. After 164 minutes (approx), the tank is near full. Following the sequence, it fills at 167 minutes.
-
12/7 minutes
-
7 minutes
-
3.5 minutes
-
None of these
A
Correct answer
Explanation
Pipe A rate = 1/3, Pipe B rate = 1/4. Combined rate = 1/3 + 1/4 = 7/12. Time = 1 / (7/12) = 12/7 minutes.
-
10.5 hours
-
12 hours
-
8 hours
-
7.5 hours
-
None of these
D
Correct answer
Explanation
Let the total work be 1 unit. Combined rate of A+B+C = 1/5. In 3 hours, they complete 3/5 of the work. Remaining work = 2/5. A and B complete this in 6 hours, so their combined rate (A+B) = (2/5) / 6 = 1/15. Rate of C = (A+B+C) - (A+B) = 1/5 - 1/15 = 2/15. Time for C = 1 / (2/15) = 7.5 hours.
-
20 hours
-
24 hours
-
40 hours
-
36 hours
-
30 hours
C
Correct answer
Explanation
Rate of filling = 1/32. Rate of emptying = 1/20. Net rate = 1/32 - 1/20 = (5 - 8) / 160 = -3/160. The cistern is 3/4 full, so we need to remove 3/4 of the total volume. Time = (3/4) / (3/160) = (3/4) * (160/3) = 40 hours.
-
15:00
-
17:00
-
18:00
-
19:00
-
20:00
C
Correct answer
Explanation
Pipe A fills 1/4 per hour. Pipe B empties 1/6 per hour. From 8:00 to 9:00, A fills 1/4. At 9:00, remaining is 3/4. Net rate = 1/4 - 1/6 = 1/12 per hour. Time to fill remaining = (3/4) / (1/12) = 9 hours. 9:00 + 9 hours = 18:00.
-
1 hour 10 minutes
-
1 hour 20 minutes
-
1 hour 40 minutes
-
1 hour 50 minutes
C
Correct answer
Explanation
Work = 5 pipes * 80 minutes = 400 pipe-minutes. 4 pipes * T = 400. T = 100 minutes = 1 hour 40 minutes.
-
60 min
-
85 min
-
90 min
-
105 min
D
Correct answer
Explanation
Rate of filling = 1/5 + 1/7 = 12/35. Rate of emptying = 1/3. Net rate = 12/35 - 1/3 = (36 - 35) / 105 = 1/105. Time = 105 minutes.
A
Correct answer
Explanation
Pipe A fills 1/12 per minute and B fills 1/16 per minute. Together they fill (1/12 + 1/16) = 7/48 per minute. For n minutes, they fill 7n/48. A then fills the remaining part in 5 minutes, which is 5/12. Equation: 7n/48 + 5/12 = 1. Solving for n gives 7n/48 = 7/48, so n = 4.
-
3 hr and 12 min
-
6 hr and 12 min
-
5 hr and 16 min
-
6 hr and 24 min
-
8 hr
D
Correct answer
Explanation
Hot pipe fills 1/8 per hr, cold pipe fills 1/12 per hr. Net fill rate = 1/8 + 1/12 = 5/24 per hr. With outlet open, rate = 5/24 - 1/6 = 1/24 per hr. In 3-hour cycles (2 hrs fill, 1 hr empty), net fill = (5/24 * 2) - (1/6 * 1) = 5/12 - 2/12 = 3/12 = 1/4. After 6 hours (2 cycles), tank is 1/2 full. In the next 2 hours, it fills 5/12, total 11/12. Remaining 1/12 takes (1/12) / (5/24) = 2/5 hours = 24 minutes. Total time = 6 hr + 24 min.
-
4t + 5t = 1
-
t/4 + t/5 = 1
-
t/(4 + 5) = 1
-
(4 + 5)/t = 1
B
Correct answer
Explanation
Pipe A fills 1/4 of the tank per hour, and Pipe B fills 1/5 of the tank per hour. Together, they fill (1/4 + 1/5) of the tank per hour. Over t hours, the total work done is t * (1/4 + 1/5) = 1, which simplifies to t/4 + t/5 = 1.
-
50 min
-
48 min
-
44 min
-
38 min
-
60 min
B
Correct answer
Explanation
Pipe A fills 1/20 per min, Pipe B 1/30 per min. Combined = 1/12 per min. In 12 mins, they fill 1 tank. If drain pipe D is open, net rate = 1/12 - 1/D. After 12 mins, they filled (1/12 - 1/D)*12. Then D closes, and A+B fill the rest in 3 mins: (1/12)*3 = 1/4. Total = 1. Solving gives D = 48.
-
36 hours
-
48 hours
-
40 hours
-
24 hours
-
20 hours
B
Correct answer
Explanation
A fills 1/24, B fills 1/30, C empties 1/60. In 2 hours (A+B), net work is (1/24 - 1/60) + (1/30 - 1/60) = 1/40 + 1/60 = 5/120 = 1/24. It takes 24 cycles of 2 hours to fill, so 48 hours.
-
25%
-
12%
-
10%
-
None of these
C
Correct answer
Explanation
P1+P2 fill rate = 1/8 + 1/12 = 5/24. P3 empty rate = 1/8. When P3 opens, net rate = 5/24 - 1/8 = 2/24 = 1/12. The tank is 1/3 full, so 2/3 remains. Time to fill 2/3 at 1/12 rate is 8 hours. Total time = (1/3)/(5/24) + 8 = 1.6 + 8 = 9.6 hours. At 9.6 hours, the tank is full. If P3 opened at 1/2, it would have been full. The fault causes 10% empty.