Quantitative Aptitude

Percentage

482 Questions
All Successive Percentage Changes 177 Population Growth and Depreciation 103 Fractional Base Multiplication 58 Reverse More-Than and Less-Than Comparisons 38 Income, Expenditure, and Savings 33 Price and Consumption 30 Election Votes and Margins 10 Fake Weight and Faulty Measures 10 Venn Diagram Percentages 9 Passing Marks Shifts 5 Fresh vs. Dry Mixture 2

Percentage Questions

Multiple choice

A local trader decided to reduce goods and service tax levied on wheat so that its cost is reduced by 23.84%. By what percentage should the sale of wheat be increased so that revenue of trader remains unchanged?

  1. 18.75%

  2. 14.89%

  3. 13.65%

  4. 31.30%

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let original price be 100 and consumption be 100. Revenue = 10,000. New price = 100 - 23.84 = 76.16. New consumption = 10,000 / 76.16 = 131.30. Increase = 31.30%.

Multiple choice

An article has a marked price of Rs. 6000 and is available at a discount of 10%. The shopkeeper gives another discount to the buyer and sells the article for Rs. 4050. What is the percentage of the second discount?

  1. 15%

  2. 20%

  3. 10%

  4. 25%
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Marked price = 6000. After 10% discount, price = 6000 - 600 = 5400. Second discount makes it 4050. Amount of second discount = 5400 - 4050 = 1350. Percentage = (1350 / 5400) * 100 = 25%.

Multiple choice

Directions: Solve the following question and mark the best possible option. In a village, the production of food grains increased by 40% and the per capita production of food grains increased by 27% during a certain period. The percentage by which the population of the village increased during the same period is nearest to

  1. 16

  2. 13

  3. 10

  4. 7
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let P be population, G be total grain, and C be per capita grain. C = G/P. New C' = 1.27C, New G' = 1.40G. New P' = G'/C' = 1.40G / 1.27C = (1.40/1.27) * P = 1.102P. The increase is approximately 10%.

Multiple choice

A species has an initial population of 410. At the end of first day, the population increases by 50%. At the end of second day, it decreases by the same percentage. If the process continues in the same pattern, the number of days for the population to reach 310 is

  1. 10

  2. 20

  3. 50

  4. 100
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initial = 4^10. Day 1 end = 4^10 * 1.5. Day 2 end = (4^10 * 1.5) * 0.5 = 4^10 * 0.75. After 2 days, factor is 0.75. After 2k days, factor is (0.75)^k. We want (4^10) * (0.75)^k = 3^10. (4/3)^10 = (1/0.75)^k = (4/3)^k. k = 10. Total days = 2k = 20.