Physics
Oscillations and Periodic Motion
162 Questions
Oscillations and periodic motion describe the movement of objects repeating their paths in regular intervals. Key concepts include simple pendulums, kinetic energy variations, and mechanical resonance. This physics topic is vital for various competitive exams.
Simple pendulumTime period calculationsKinetic energy in SHMMechanical resonanceDamped oscillations
Oscillations and Periodic Motion Questions
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24 Hours
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9.8 Secs
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Infinite
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1 Year
C
Correct answer
Explanation
At the center of the Earth, the effective gravitational acceleration (g) becomes zero because the mass of the Earth is symmetrically distributed around that point, canceling out all gravitational forces. Since the time period formula T = 2π√(L/g) would result in division by zero, the time period becomes theoretically infinite.
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Increase
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Decrease
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Remains same
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Depends on mass of Pendulum
A
Correct answer
Explanation
The time period of a simple pendulum is T = 2π√(L/g), where L is length and g is gravitational acceleration. The Moon's gravity is about 1/6th of Earth's gravity, so the denominator decreases, making T increase. The period does NOT depend on the mass of the pendulum bob.
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The same way
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Inversely
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As a multiple
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Directly
B
Correct answer
Explanation
For a simple pendulum, frequency f = (1/2π)√(g/L), meaning frequency decreases as length increases. It's inversely proportional to the square root of length, so 'inversely' is the correct choice among the given options. A longer pendulum swings fewer times per second.
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The period increases and the clock loses time
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The period increases and the clock gains time
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The period decreases and the clock gains time
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The period remains constant and the clock maintains correct time
D
Correct answer
Explanation
The period of a simple pendulum depends only on its length (T = 2π√(L/g)) and is independent of mass. Changing the pendulum bob's mass doesn't affect the period, so the clock continues to keep correct time. The pendulum's timekeeping is based on length and gravity, not mass.
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Directly
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the same way
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multiple directly
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Inversly
D
Correct answer
Explanation
For a simple pendulum, frequency decreases as length increases. The exact relationship is f ∝ 1/√L, meaning frequency is inversely related to the square root of length. Option D captures this inverse relationship.
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never becomes zero
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becomes zero in each turn
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becomes zero in equilibrium case
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always remains the same
B
Correct answer
Explanation
At the extreme positions of its swing (maximum amplitude), a simple pendulum momentarily comes to rest as it changes direction. At this point, its kinetic energy is zero. The kinetic energy then increases as it accelerates toward the lowest point, converting potential energy to kinetic energy.
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shape of the bob
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size of the bob
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length of the string
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density of the bob
C
Correct answer
Explanation
The time period of a simple pendulum is given by T = 2π√(L/g), where L is the length of the string and g is acceleration due to gravity. The time period depends only on the length and gravitational acceleration, not on the mass, shape, size, or density of the bob.
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run slow
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run fast
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give the same time
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stop altogether
A
Correct answer
Explanation
The acceleration due to gravity (g) is higher at the poles than at the equator due to Earth's shape (oblate spheroid) and rotational effects. Since the time period of a pendulum is T = 2π√(L/g), a higher g means a shorter time period. The clock completes each swing faster, so it effectively runs slow (loses time) when compared to its rate at the equator.
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Only a
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Only a and b
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Only b
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Only b and c
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Only c
E
Correct answer
Explanation
This is a false statement. Thus, it is a correct option. The time-period of a pendulum depends only on the length of the pendulum and not on the amplitude of vibrations.
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Both A and B run faster than C
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Both A and B run slower than C
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A runs slower than C but runs faster than C
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B runs slower then C but A runs faster than C
B
Correct answer
Explanation
Pendulum period depends on gravity (T = 2π√(l/g)). At a mountain top, g is lower, so period increases (runs slower). In a deep mine, g is also lower due to mass being above, so period also increases (runs slower). Both A and B run slower than C.
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Balance wheel
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Quartz
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Pendulum
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Cesium atoms
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None of these
D
Correct answer
Explanation
Yes, it is correct. The cesium atomic clocks are very accurate.
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decreases
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increases
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remains constant
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either increases or decreases
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none of these
B
Correct answer
Explanation
The time period of simple pendulum is given by
T = 2π√(L / g).
On the moon, g is much smaller as compared to g on earth. Therefore, T increases.
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Random motion
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Oscillatory motion
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Circular motion
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Curvilinear motion
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Periodic motion
B
Correct answer
Explanation
Oscillatory motion: The 'to and fro' motion of a body, e.g. motion of a swing, movement of the 'bob' of a pendulum in a clock etc.
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3 s
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75 s
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0.33 s
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0.066 s
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15 s
A
Correct answer
Explanation
The time taken by the pendulum to complete 5 oscillations = 15 s
The time taken by the pendulum to complete 1 oscillation = 15/5 = 3 s
Therefore, time period = 3 s
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remains the same
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decreases
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increases
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becomes zero
C
Correct answer
Explanation
The time period of a simple pendulum depends on gravitational acceleration (T = 2π√(L/g)). On the Moon, gravity is about 1/6th of Earth's gravity, so the pendulum swings slower and takes more time to complete one oscillation. The time period increases by a factor of √6.