Physics · Science General
Optics and Light Properties
2,019 Questions
Optics and light properties focus on the behavior of light, including reflection, refraction, dispersion, and polarization. This topic also covers the wave nature of light, illumination, and the functioning of optical instruments like microscopes. Questions on these concepts are common in general science sections of SSC, Railways, and State exams.
Reflection and mirrorsRefraction and mediumsLight wave theoriesPolarization and intensity
Optics and Light Properties Questions
When the light is incident at the polarizing angle on transparent medium, then the completely polarized light is
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refracted light
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reflected light
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refracted and reflected light
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neither reflected nor refracted light
B
Correct answer
Explanation
When the light is incident at the polarising angle on the transparent medium, the reflected light is completely polarised.
The transverse nature of light is shown by
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interference of light
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refraction of light
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polarization of light
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dispersion of light
C
Correct answer
Explanation
Polarisation of light establishes that light are transverse in nature, otherwise it was believed that they are longitudinal waves, like the sound waves.
Polarisation of light establishes
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corpuscular theory of light
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quantum nature of light
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transverse nature of light
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all of the above
C
Correct answer
Explanation
Polarisation of light establishes that light are transverse in nature, otherwise it was believed that they are longitudinal waves, like the sound waves.
A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\phi$. If $\mu$ represents the refractive index of glass with respect to air, then the angle between the reflected and the refracted rays is
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90$^o$ + $\phi$
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$sin^{-1}$( $ \mu cos \phi$)
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90$^o$
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90 $-sin^{-1}$ $\left (\displaystyle \frac{sin\phi }{\mu}\right )$
C
Correct answer
Explanation
When angle of incidence is equal to the Brewster's angle then, the angle between reflected and refracted rays is $ { 90 }^{ o }$
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can detect polarized light
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cannot detect polarization of light
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can detect only circularly polarized light
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can detect only linearly polarized light
B
Correct answer
Explanation
Polarization changes when plane of vibration of polarized light changes.
Human eye is insensitive to change in polarization and hence, cannot detect polarization of light.
Polarisation of light was first successfully explained by:
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Corpuscular theory
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Huygens' wave theory
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Electromagnetic wave theory
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Planck's theory
C
Correct answer
Explanation
Electromagnetic wave theory explains light as being composed of electric field vibrating in planes.
Polarisation of light refers to vibrating electric field in a particular plane.
When light is incident on a glass block at polarizing angle
a) reflected ray is plane polarized
b) reflected and refracted rays are perpendicular
c) reflected and refracted rays are partially polarized
d) refracted ray is partially polarised
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a, c and d are correct
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a, b and d are correct
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b, c and d are correct
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a, b and c are correct
B
Correct answer
Explanation
when a beam of unpolarized light is incident on the glass block, certain amount of the incident vibration is reflected in a plane perpendicular to the plane of incidence and transmits the rest.
Thus reflected ray is completely polarized but not partially polarized.
Thus only (c) is wrong and rest options are correct.
The polarising angle for glass is :
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same for different kinds of glass
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different for different kinds of glass
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same for lights of all colours
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varies with time
B
Correct answer
Explanation
Different kinds of glass have different refractive index. Thus as polarising angle depends on refractive index the polarising angle is different for different kinds of glass. $tan \ i = \mu $
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Interference by splitting the wave front
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Polarisation by reflection
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Polarisation by refraction
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Polarisation by double refraction
D
Correct answer
Explanation
In 1669, another Danish scientist, Erasmus Bartholinus discovered the polarization of light by double refraction in Iceland spar (calcite).
Choose the correct statements among the following given options.
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Brewster's angle is independent of wavelength of light.
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Brewster's angle is independent of the nature of reflecting surface.
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Brewster's angle is different for different wavelengths.
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Brewsters angle depends on wavelength but not on the nature of reflecting surface.
C
Correct answer
Explanation
Brewster's angle is an angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface,
with no reflection.
$\theta _{B}=tan^{-1}(\dfrac{n _{2}}{n _{1}})$
$n _{2}$ refractive index of final medium
$n _{1}$ refractive index of initial medium
As different wavelength have different refractive indices the brewster angle is also different.
Pile of plates can be used to produce completely polarised light due to :
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Reflection
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Refraction
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Double refraction
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A and B
B
Correct answer
Explanation
pile of plates is used to produce plane polarized light by refraction.
By refraction through multiple plates vibrations in the plane of incidence are transmitted.
Thus we obtain a polarized light.
At the polarising angle $(\theta _{B})$, angle of refraction is given by :
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$90^{\circ}$
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$90^o+\theta _{B}$
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$90^o-\theta _{B}$
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$\dfrac{90^o}{\theta _B }$
C
Correct answer
Explanation
At polarizing angle $\theta _{B}$
$\dfrac{sin \theta _{B}}{cos \theta _{B}}=\dfrac{sin \theta _{B}}{sin \gamma }$
we get $sin \gamma =cos \theta _{B}$
$sin \gamma =sin(90-\theta _{B})$
Thus $\gamma =90-\theta _{B}$
The angle of incidence at which reflected light is totally polarised for reflection from air to glass (refractive index n) is :
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$sin^{-1}(n)$
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$sin^{-1}(1/n)$
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$ tan^{-1}(n)$
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$ tan^{-1}(1/n)$
C
Correct answer
Explanation
The refractive index of glass is n
If the light is incident on the surface with an angle of incidence i given by tan i $=\mu $ using the Brewster's law the reflected light is completely polarized.
Here tan i $=n$
i$=tan^{-1}(n)$
A light ray is incident on a transparent medium of $\mu =$ 1.732 at the polarizing angle. The angle of refraction is :
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60$^{\circ}$
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30$^{\circ}$
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45$^{\circ}$
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90$^{\circ}$
B
Correct answer
Explanation
Angle of incidence $=$ polarising angle
$tan i = \mu $
$tan i = 1.732$
$i = 60^{0}$
From snell's law
$\dfrac{sin i}{sin \gamma }=\mu $
$sin \gamma =\dfrac{sin 60^{0}}{1.732}$
$\gamma =30^{0}$
The critical angle for total internal reflection for a substance is $45^{\circ}$. The polarizing angle for this substance is ($\tan 54^{\circ}44'=\sqrt{2}$) :
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$46^{\circ}16'$
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$54^{\circ}44'$
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$46^{\circ}44'$
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$54^{\circ}16'$
B
Correct answer
Explanation
If polarizing angle is $\theta $
Then tan $\theta =\dfrac{1}{sin c}$
$tan \theta =\dfrac{1}{sin 45}=\sqrt{2}$
$\theta =54^{0}{44}'$