Physics
Optical Instruments and Human Eye
416 QuestionsOptical instruments and the human eye explore how lenses and mirrors are used to magnify and resolve images. Key topics include the magnifying power of astronomical telescopes, compound microscope configurations, and hyperfocal distance calculations. These physics concepts are vital for general science competitive exams.
Optical Instruments and Human Eye Questions
What is the maximum size to which you magnify the picture?
The focal length of a lens can be expressed in :
The focal length can be expressed in:
Point like object is observed using microscope angle subtended by objective with object is $20^{\circ}$. If oil of refractive index $1.4$ is kept between object and objective, numerical aperture will be ________.
Which of the following is the best method to measure microscopic distances?
A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm is:
A telescope is used to resolve two stars separated by $4.6 \, \times \, 10^{-6}$ rad. If the wavelength of light used is 5460 $\overset{0}{A}$, what should be the aperture of the objective of the telescope?
In an astronomical telescope of refracting type:
Four lenses of focal length $+15cm,+20cm,+150cm$ and $+250cm$ are available for making an astronomical telescope. To produce the largest magnification, the focal length of the eyepiece should be
The objective of a telescope A has diameter 3 times that of the objective of telescope B, How much greater amount of light is gathered by A as compared to B?
In telescope, ratio of resolving power due to light of $\lambda=400\mathring {A}$ and $\lambda =6000\mathring {A}$ is ______
For an electron microscope, which of the following is false ?
If an object subtend angle of $2^o$ at eye when seen through telescope having objective and eyepiece of focal length $f = 60\, cm $and $f = 5\, cm$ respectively than angle subtend by image at eye piece will be