Quantitative Aptitude · Mathematics
Numbers and Divisibility
209 Questions
Master the number system by solving these quantitative aptitude questions on divisibility rules and properties. The exercises cover finding the greatest common divisor and identifying prime factors. This topic is essential for clearing the preliminary stages of SSC, banking, and various state exams.
Divisibility rulesGreatest common divisorPolynomial divisionNatural numbersFactorizationPrime numbers
Numbers and Divisibility Questions
B
Correct answer
Explanation
A number is divisible by 7 if unit's place digit is multiplied by 2 and subtracted from the remaining digits and the number obtained is divisible by 7. 47331- (2*2) = 473274732 - (7*2) = 4718471 - (8*2) = 45545 - (5*2) = 3535 is divisible by 7.Therefore, 473312 is divisible by 7. It is the correct answer.
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256478
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546323
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236940
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1, 2 and 3
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Only 1 and 2
B
Correct answer
Explanation
It is not divisible by 2.
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28405
-
24805
-
28540
-
None of these
A
Correct answer
Explanation
Numbers between 500 and 1000 divisible by 13 are: 507 (13×39), 520 (13×40), ..., 988 (13×76). This is an AP with first term 507, last term 988, and 38 terms. Sum = 38/2 × (507 + 988) = 19 × 1495 = 28405.
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10200
-
15200
-
16200
-
None of these
C
Correct answer
Explanation
Use inclusion-exclusion: Sum of multiples of 4 (10200) + Sum of multiples of 5 (8200) - Sum of multiples of 20 (2200, counted twice). Total = 10200 + 8200 - 2200 = 16200.
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2200
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2000
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2220
-
None of these
A
Correct answer
Explanation
Numbers divisible by both 4 and 5 are divisible by LCM(4,5)=20. Multiples of 20 from 100 to 300 are: 100, 120, ..., 300. This is 11 terms. Sum = 11/2 × (100 + 300) = 11/2 × 400 = 2200.
A
Correct answer
Explanation
x + 2 is a factor x = - 2 makes it zero
(-2)3 + 6(-2)2 + 4(-2) + k = 0 i.e k = - 8
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8700
-
8810
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8820
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9930
-
None of these
C
Correct answer
Explanation
To find greatest which is divisible by 21, 18, 12 and 15, we shall have to find the LCM of 21-18-12-15 which is 1260. After dividing 9999 by 1260 we get 1179 remainder. So answer will be 9999-1179 = 8820
E
Correct answer
Explanation
n3 - n = (n - 1) (n) (n + 1), for integral values of n, represents the product of three consecutive integers. Since in a pair of consecutive integers, there is a multiple of two and in a triplet of consecutive integers, there is a multiple of three, then n3 - n is divisible by 6. Hence, option (5) is the correct option.
E
Correct answer
Explanation
Options 2 and 4 both are correct as for m = 1 and 2, the numbers so formed are not divisible by 3.
D
Correct answer
Explanation
214984 + 2 = 214986 (divisible by 3)
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13 K + 1333 L
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13 K + 1336 L
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13 K + 1339 L
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13 K + 1337 L
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None of these
C
Correct answer
Explanation
13 K + 1339 L = 13 (K + 103)
D
Correct answer
Explanation
If a number is divisible by both 2 and 3 then it is divisible by 6 also
-
3333333
-
1111111
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22222222
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None of these
C
Correct answer
Explanation
On applying the divisibility rule of 11, We get, sum of odd terms=8 and sum of even terms=8 Difference= 8-8=0, which is divisible by 11
D
Correct answer
Explanation
[Explanation: Find the sum of digits as 6+3+9+2+1+0=21 which divisible by 3 but not by 9]
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96354142
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37450176
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57064214
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98671402
B
Correct answer
Explanation
[Explanation: On applying the divisibility rule of 8, i.e., last 3 digits of the number are divided By 8, 176/8= 22 and remainder as 0 This means, 37450176 which is divisible by 8]