Number Operations and Properties

Unit digits of both numbers are $6$ and $8$. 

The resultant product of $3$ negative signs would be negative.

$(100 + 2) \times (100 + 3)$
           [Using $(x +a) (x+b)=x^2+(a+b)x+ ab$]
$ = (100)^2 + (2 + 3) \times 100 + 2 \times 3$
$ = 10000 + 5 \times 100 + 6 = 10000 + 500 + 6 = 10506$

Let, $\frac {2x}{3}=96$
$x=\frac {96\times 3}{2}=144$
$\therefore \frac {3}{4}\times 144=3\times 36=108$

$1+9\times 10 = 91$

Let the number is x

$46)57804(1256$
$\underline {46}$
$118$
$\underline {92}$
$260$
$\underline {230}$
$304$
$\underline {276}$
$\underline {28}$

$7986$
$\underline {\times 548}$
63888
319440
$\underline {3993000}$
$\underline {4376328}$

(98+ 14) $\displaystyle \times $ 0 = 0

$3897\times 999=3897\times (1000-1)$
$=3897\times 1000-3897\times1$
$=3897000-3897$
$=3893103$

$\ \ \ \ \ \ \ \ 34 \ \times\ \ \ \  56 \ ----$

$16974\div 23\div 2$

$\ \ \ \ 12340\ \times \ \ \ \ \ \ 23 \ ---- \ \ \ \ \ \ \ 37020 \ + 246800 \ ---- \ \ \ \ \ 283820$