Mathematics · Quantitative Aptitude

Number Operations and Properties

896 Questions

Improve your quantitative aptitude with these number operations and properties questions. The topics range from basic subtraction and division to highest common factor and roman numerals. Regular practice of these fundamentals builds speed for exams.

Basic arithmetic operationsHCF and number propertiesRoman numeral calculationsNumber series evaluation

Number Operations and Properties Questions

Multiple choice maths negative numbers and integers even and odd numbers sum of numbers odd and even numbers

Sum of one odd and one even integers is :

  1. Even

  2. Odd

  3. Both

  4. Can't be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

An even integer is an integer that is evenly divisible by $2$, that is, division by $2$ results in an integer without any remainder. The set of even integers is:


$.....-8,-6,-4,-2,2,4,6,8,.....$

Whereas, an odd integer is an integer that is not divisible by $2$. The set of odd integers is:

$.....-9,-7,-5,-3,-1,1,3,5,7,9.....$

Now let us take an even integer say, $2$ and an odd integer say $3$, then their sum will be $2+3=5$ which is an odd integer.

Hence, the sum of one odd and one even integer is always odd.

Multiple choice maths negative numbers and integers even and odd numbers sum of numbers odd and even numbers

Sum of two even integers is :

  1. Even

  2. Odd

  3. Both

  4. Can't be determined
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

An even integer is an integer that is evenly divisible by $2$, that is, division by $2$ results in an integer without any remainder. The set of even integers is:


$.....-8,-6,-4,-2,2,4,6,8,.....$

Now let us take two even integers say, $2$ and $4$, then their sum will be $2+4=6$ which is also an even integer.

Hence, the sum of even integers is always even.

Multiple choice maths brackets order operations and algebra using brackets in algebraic expressions order of operations

The value of $100 - { ( 7 $of $8 + 4 ) \div 5 } $ is

  1. $92$
  2. $78$
  3. $96$
  4. $88$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

We apply BODMAS rule to find the value of the given expression. According to BODMAS rule, if an expression contains brackets we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.


Since 'of' stands for multiplication, therefore the given expression becomes 
$100-[(7\times 8+4)\div 5]$ and apply BODMAS rule as shown below:
$ \Rightarrow 100-[(56+4)\div 5]\ \Rightarrow 100-(60\div 5)\ \Rightarrow 100-12\ \Rightarrow 88$
Hence, the value of $100-[(7\times 8+4)\div 5]$ is $88$.

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

Which of the following expressions is true?

  1. $2940000=$$\displaystyle 2\cdot 94\times 10^{5}$
  2. $502000=$$\displaystyle 5\cdot 02\times 10^{5}$
  3. $3683000=$$\displaystyle 3\cdot 683\times 10^{5}$
  4. $40404000=$$\displaystyle 4\cdot 0404\times 10^{5}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\displaystyle 502000= 5\cdot 02\times 10^{5}$

Therefore, option B is correct.

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

When $70, 000$ is written as $7.0\times10^n$, what is the value of $n$?

  1. $1$
  2. $2$
  3. $3$
  4. $4$
  5. $5$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given that $70,000$ is written as $7.0$ $\times $ ${10}^{n}$

From this, we can write
$70,000$ $=$ $7.0$ $\times$ ${10}^{n}$
$\Rightarrow {10}^{n}$ $=$ $\dfrac {70,000}{7}$
$\Rightarrow {10}^{n}$ $=$ $10,000$
$\Rightarrow {10}^{n}$ $=$ ${10}^{4}$
$\Rightarrow n$ $=$ $\log _{10}$ ${10}^{4}$
$\Rightarrow n$ $=$ $4$ $\log _{10}$ $10$
$\Rightarrow $ $=$ $4$
Therefore, the value of $n$ is $'4'$.

Multiple choice maths square and square root perfect square or square number squares and triangles powers and roots

Find the value of each of the following, using the column method.
$(23)^2$
$(52)^2$

  1. 549, 2724

  2. 549, 2704

  3. 529, 2724

  4. 529, 2704
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$(23)^2$
$a=2, b=3$

$i$ $ii$ $iii$
$a^2$ $2ab$ $b^2$
$4$$1$           $\underline { 5 }$ $12$$+0$           $1\underline { 2 }$ $\underline { 9 }$

$\therefore (23)^2=529$

$(52)^2$
$a=5, b=2$

$i$ $ii$ $iii$
$a^2$ $2ab$ $b^2$
$25$$+2$          $\underline { 27 }$ $20$$+0$          $2\underline { 0 }$ $\underline { 4 }$

$\therefore (52)^2=2704$