Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
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27 : 37
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26 : 38
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1 : 4
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27 : 64
A
Correct answer
Explanation
The amount of milk remaining after 3 operations is 40 * (1 - 10/40)^3 = 40 * (3/4)^3 = 40 * 27/64 = 16.875. The water is 40 - 16.875 = 23.125. The ratio 16.875 : 23.125 simplifies to 27 : 37.
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3 : 2
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2 : 5
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2 : 3
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None of the above
C
Correct answer
Explanation
Alloy A: 14 kg, ratio 3:4 (Total parts 7). Metal 1 = 14 * 3/7 = 6, Metal 2 = 8. Alloy B: 26 kg, ratio 5:8 (Total parts 13). Metal 1 = 26 * 5/13 = 10, Metal 2 = 16. Total Metal 1 = 6+10=16, Total Metal 2 = 8+16=24. Ratio = 16:24 = 2:3.
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33 : 3.3 : 2.2
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5 : 7 : 8
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1 : 3 : 4
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2 : 3 : 4
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2 : 3 : 9
D
Correct answer
Explanation
Initial ratio 5:7:8. New quantities: 5*1.4 = 7, 7*1.5 = 10.5, 8*1.75 = 14. Ratio 7 : 10.5 : 14. Multiply by 2: 14 : 21 : 28. Divide by 7: 2 : 3 : 4.
A
Correct answer
Explanation
Each stroke removes 1/2, leaving 1/2. After 4 strokes, the remaining fraction is (1/2)^4 = 1/16.
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57 : 125
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68 : 125
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57 : 68
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68 : 90
C
Correct answer
Explanation
Initial: 120L, 2:3 ratio -> 48L milk, 72L water. Increase volume by 25% (30L) by adding water: 48L milk, 102L water. Total 150L. Draw 30L: Ratio is still 48:102 (or 8:17). 30L contains (8/25)*30 = 9.6L milk and 20.4L water. Remaining: 38.4L milk, 81.6L water. Add 30L milk: 68.4L milk, 81.6L water. Ratio 68.4/81.6 = 684/816 = 57/68.
A
Correct answer
Explanation
Initial salt = 4 * 0.15 = 0.6 litres. After 1.5 litres spills, remaining solution = 2.5 litres. Remaining salt = 2.5 * 0.15 = 0.375 litres. Jug filled to 5 litres with water. New concentration = 0.375 / 5 = 0.075 = 7.5%.
D
Correct answer
Explanation
The final temperature is calculated using the principle of heat exchange: m1*c*(T-T1) = m2*c*(T2-T). With 50g at 30C and 200g at 100C, the equation is 50(T-30) = 200(100-T), which simplifies to T-30 = 400-4T, or 5T = 430, resulting in T = 86C.
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8 litre
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5 litre
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6 litre
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10 litre
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9 litre
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65.61 litres
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75.71 litres
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80 litres
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70 litres
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60 litres
A
Correct answer
Explanation
The formula for remaining quantity is Initial * (1 - removed/total)^n. Here, 100 * (1 - 10/100)^4 = 100 * (0.9)^4 = 100 * 0.6561 = 65.61.
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1 : 2
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1 : 3
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2 : 3
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2 : 5
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4 : 5
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Rs. 63.75
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Rs. 63.35
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Rs. 62.83
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Rs. 62.45
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Rs. 62.23
B
Correct answer
Explanation
Let the cost of first quality be x and second be x + 3.25. Ratio 4:1. Total cost = (4x + 1(x + 3.25)) / 5 = (5x + 3.25) / 5 = x + 0.65. Selling price = 72, profit 12.5%. Cost = 72 / 1.125 = 64. So x + 0.65 = 64, x = 63.35.
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38 litres
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40 litres
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44 litres
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50 litres
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54 litres
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2 : 3
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3 : 2
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1 : 2
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8 : 9
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9 : 8
A
Correct answer
Explanation
Using the alligation method: (40-30) / (30-15) = 10 / 15 = 2 / 3. The ratio is 2:3.
C
Correct answer
Explanation
Initial ratio 1:4 means 1 unit sugar, 4 units water (total 5). If it loses 50% weight, 2.5 units remain. Since sugar is non-volatile, 1 unit of sugar remains, and 1.5 units of water remain. The new ratio is 1:1.5, which is 2:3.