Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
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$1:4$
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$1:8$
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$7:32$
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$3:16$
C
Correct answer
Explanation
Moles = Mass / Molar Mass. Ratio of moles = (1/32) : (4/28) = (1/32) : (1/7) = 7 : 32.
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$35\%$
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$40\%$
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$50\%$
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$60\%$
D
Correct answer
Explanation
CO + CO2 -> 2CO. Let x be volume of CO2. Volume of CO = 1-x. Increase in volume = x = 0.6 L. CO2 = 60 percent.
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$50\ cm^{3}$
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$60\ cm^{3}$
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$70\ cm^{3}$
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$80\ cm^{3}$
C
Correct answer
Explanation
According to Graham's Law of Diffusion, the rate of diffusion is inversely proportional to the square root of the molar mass. For H2 (mass 2) and O2 (mass 32), the ratio of rates is sqrt(32/2) = 4. With a 2:1 volume ratio, the diffusion ratio is (2 * 4) : (1 * 1) = 8:1.
A
Correct answer
Explanation
Formic acid (HCOOH) + H2SO4 -> CO + H2O. Oxalic acid (H2C2O4) + H2SO4 -> CO + CO2 + H2O. KOH absorbs CO2. Let x be moles of formic and y be moles of oxalic. CO2 produced = y. Total gas = x + 2y. Volume decrease = y. Given y / (x + 2y) = 1/6. 6y = x + 2y, so x = 4y. Ratio x:y = 4:1.
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$1 : 2 : 8$
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$7 : 10 : 20$
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$1.414 : 2 : 4$
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None of the above
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$n_{N_2} : n_{CO} : : 1 : 2$
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$n_{N_2} : n_{CO} : : 6 : 1$
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$n_{CO} : n_{N_2} : : 1 : 2$
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$n_{CO} : n_{N_2} : : 2 : 3$
D
Correct answer
Explanation
According to Graham's Law of Effusion, the rate of effusion is inversely proportional to the square root of the molar mass. Rate(N2)/Rate(CO) = (n_N2/n_CO_initial) * sqrt(M_CO/M_N2). Given n_N2/n_CO = 3/2 and M_N2=28, M_CO=28, the ratio is (3/2) * sqrt(28/28) = 3/2. Thus n_CO/n_N2 = 2/3.
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$\dfrac {1}{8}$
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$\dfrac {1}{12}$
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$\dfrac {1}{16}$
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$\dfrac {1}{24}$
D
Correct answer
Explanation
According to Graham's Law of Diffusion, the rate of diffusion is inversely proportional to the square root of the molar mass. For H2 (M=2) and O2 (M=32), the rates are in ratio (3/sqrt(2)) : (1/sqrt(32)). This simplifies to (3/sqrt(2)) : (1/(4*sqrt(2))), which is 12:1.
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1 : 1 : 1 : 1
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1 : 2 : 2 : 3
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2 : 1 : 3 : 4
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3 : 2 : 2 : 1
C
Correct answer
Explanation
All flasks have same volume, temperature, and pressure, so they contain the same number of molecules (Avogadro's Law). N2 has 2 atoms, Ne has 1, N2O has 3, SO3 has 4. Ratio is 2:1:3:4.
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$0.8\ g/ml$
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$1.0\ g/ml$
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$1.25\ g/ml$
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$1.33\ g/ml$
C
Correct answer
Explanation
Concentration w/v = (w/w) * density. Given 25% (w/v) = 20% (w/w) * density, density = 25 / 20 = 1.25 g/ml.
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$61.63$
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$38.37$
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$50$
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$28.3$
D
Correct answer
Explanation
Total Kinetic Energy = 3/2 * n * R * T. With T=250K, 3000 = 1.5 * n * 8.314 * 250, so n = 3000 / 3117.75 = 0.9622 moles. Let m be mass of Ne, then (m/20) + ((30-m)/40) = 0.9622. Multiplying by 40: 2m + 30 - m = 38.488, so m = 8.488g. Mass % = (8.488/30)*100 = 28.29%.