Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
A
Correct answer
Explanation
In a 126L mixture with milk:water = 5:7, we have 52.5L milk and 73.5L water. To make them equal (63L each), we need to add 10.5L milk and remove 10.5L water. When we remove x liters of mixture and replace with pure milk: milk removed = (5/12)x, water removed = (7/12)x. Final milk = 52.5 - (5/12)x + x, Final water = 73.5 - (7/12)x. Setting equal: 52.5 + (7/12)x = 73.5 - (7/12)x, which gives x = 18L. Verification: Remove 18L (7.5L milk, 10.5L water), add 18L pure milk. New milk = 52.5 - 7.5 + 18 = 63L, New water = 73.5 - 10.5 = 63L. Ratio is 1:1.
A
Correct answer
Explanation
Each operation removes 15L milk and adds 15L water. After 3 operations, milk remaining = V*(1-15/V)^3 where V is initial volume. Water remaining = V - milk remaining. Ratio milk:water = 343:169, so milk/total = 343/512. Thus (1-15/V)^3 = 343/512, giving 1-15/V = 7/8, so V = 120L.
B
Correct answer
Explanation
Sangram bought 30 kg at Rs 9.50/kg and 30 kg at Rs 8.50/kg, so total quantity = 60 kg. Total cost = (30 × 9.50) + (30 × 8.50) = 285 + 255 = Rs 540. Average cost per kg = 540/60 = Rs 9/kg. He sold at Rs 8.90/kg, so selling price = 60 × 8.90 = Rs 534. Loss = Cost - Selling price = 540 - 534 = Rs 6. This matches option B. The question asks for profit or loss, and since it's a loss, the answer is 6.
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243:945
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361:1890
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143:1890
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123:945
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None of these
C
Correct answer
Explanation
Calculate alcohol fraction in mixture: (5/9 + 4/7 + 5/9)/3 = 139/315. Set up replacement equation to achieve 1:1 ratio. The replacement fraction is 143:1890, making option C correct. Options A, B, and D have calculation errors.
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$13: 15$
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$17: 11$
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$11: 13$
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$15: 13$
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$11: 17$
D
Correct answer
Explanation
First vessel (10L, 75% acid): 7.5L acid + 2.5L water. Second vessel (15L, 70% water): 4.5L acid + 10.5L water. Combined: 12L acid + 13L water = 25L. Large vessel needs 3L more acid to reach 28L capacity. Final: 15L acid + 13L water, giving ratio 15:13.
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6 litres
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6.5 litres
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7 litres
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7.5 litres
B
Correct answer
Explanation
In 3.5 L of first mixture (4:3), honey = 2 L, water = 1.5 L. Adding x litres of second mixture (6:7) gives honey = 2 + 6x/13 and water = 1.5 + 7x/13. Setting these equal for 1:1 ratio gives x = 6.5 L.
D
Correct answer
Explanation
Each replacement operation removes 3 liters from 30, which is 10%. After first operation: water = 30 × 0.9 = 27 liters. After second operation: water = 27 × 0.9 = 24.3 liters. Each operation preserves 90% of the water remaining. Sprit quantity = 30 - 24.3 = 5.7 liters.
A
Correct answer
Explanation
This is an alligation problem. To find the ratio, use the alligation method: (60-50):(50-30) = 10:20 = 1:2. This means we need 2 parts of the 60% mixture and 1 part of the 30% mixture. The final ratio is 2:1 (first barrel:second barrel).
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12
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14
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15
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16
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none of these
D
Correct answer
Explanation
Initial mixture has 24L alcohol + 72L water = 96L total (25% alcohol). When x litres of mixture is removed, the proportion remains the same, so 0.25x alcohol and 0.75x water are removed. After adding 16L alcohol and 24L water, final mixture has (40-0.25x) alcohol and (96-0.75x) water. Total volume is (136-x) litres. Given that alcohol is 30% of final mixture: (40-0.25x)/(136-x) = 0.30. Solving gives 0.05x = 0.8, so x = 16 litres.
B
Correct answer
Explanation
When water is added to milk and sold at cost price, the profit percentage equals the percentage of water added to the milk. Here, 35% profit means water constitutes 35% of the milk quantity. Water added = 35% of 40L = 0.35 × 40 = 14 liters. After adding 14L water, total volume becomes 54L, but the cost is only for 40L of milk. Selling 54L at the price of 40L gives a profit of 14L on 40L, which is exactly 35%.
D
Correct answer
Explanation
In 84L, milk:water = 3:4, so milk = 36L, water = 48L. After adding x liters water, milk percentage = 36/(84+x) = 37.5% = 3/8. Solving: 288 = 252 + 3x, so x = 12L.
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$6: 7$
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$7: 5$
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$4 : 3$
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$5: 6$
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$3: 2$
B
Correct answer
Explanation
Alloy P: Gold:Copper = 7:2, so Gold = 7/9, Copper = 2/9. Alloy Q: Gold:Copper = 7:11, so Gold = 7/18, Copper = 11/18. Equal quantities mixed: Total Gold = 7/9 + 7/18 = 14/18 + 7/18 = 21/18 = 7/6. Total Copper = 2/9 + 11/18 = 4/18 + 11/18 = 15/18 = 5/6. Ratio Gold:Copper = 7:5.
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18 litres
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30 litres
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24 litres
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28 litres
B
Correct answer
Explanation
Initial ratio 4:3 means 4x milk and 3x water. After adding 2 liters water, ratio becomes 8:7. Cross-multiplying: 28x = 24x + 8, giving 4x = 8, so x = 2. Initial mixture is 7x = 14 liters. Final mixture after adding 2 liters is 16 liters. Wait - let me recalculate: 28x = 24x + 8 gives x = 2, initial = 14, final = 16. But option B says 30. Let me verify: 4x/(3x+2) = 8/7 gives 28x = 24x + 16, so 4x = 16, x = 4. Initial = 28 liters, final = 30 liters.
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27: 38
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22: 27
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35: 22
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27: 22
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22: 35
E
Correct answer
Explanation
Let the blends be mixed in ratio x:y. First blend: Darjeeling fraction = 4/11, Assam = 7/11. Second blend: Darjeeling = 2/7, Assam = 5/7. Final mixture: Darjeeling = 6/19, Assam = 13/19. Using allegation: (4/11)x + (2/7)y / (x+y) = 6/19. Cross-multiply: 19(4/11)x + 19(2/7)y = 6x + 6y. Solving gives x:y = 22:35. Verify: (4/11)(22) + (2/7)(35) = 8 + 10 = 18, and (7/11)(22) + (5/7)(35) = 14 + 25 = 39, ratio 18:39 = 6:13.
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$1:2$
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$5:1$
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$4:1$
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$2:1$
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$None of these$
D
Correct answer
Explanation
Initial mixture: 80L with milk:water = 4:1, so milk = 64L, water = 16L. First removal: 20L taken out (maintaining 4:1 ratio), so 16L milk + 4L water removed. Remaining: 48L milk, 12L water. Add 12L milk: 60L milk, 12L water. Second removal: 24L taken out (ratio 5:1), so 20L milk + 4L water removed. Remaining: 40L milk, 8L water. Add 12L water: 40L milk, 20L water. Final ratio = 40:20 = 2:1. Option D is correct.