Mixtures and Alligation Questions

Multiple choice
  1. 2 : 5

  2. 12 : 5

  3. 5 : 12

  4. 7 : 3

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Use alligation. Vessel A: 1/5 milk. Vessel B: 5/8 milk. Target: 1/2 milk. |5/8 - 1/2| = 1/8. |1/2 - 1/5| = 3/10. Ratio = (1/8) / (3/10) = 10/24 = 5/12.

Multiple choice
  1. 15 kg

  2. 19 kg

  3. 20 kg

  4. 23 kg

  5. 25 kg

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The selling price is 2280 with a 20% profit, so the cost price is 2280 / 1.2 = 1900. Let x be the quantity of inferior sugar; then 50 * 30 + x * 20 = 1900. Solving for x gives 1500 + 20x = 1900, so 20x = 400, meaning x = 20 kg.

Multiple choice
  1. 3 kg

  2. 4 kg

  3. 5 kg

  4. 7 kg

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Alloy A: 20kg (2:3) -> 8kg Cu, 12kg Sn. Alloy B: 28kg (3:4) -> 12kg Cu, 16kg Sn. Total Cu = 20 + x, Total Sn = 28. Ratio (20+x)/28 = 6/7. 7(20+x) = 168. 140 + 7x = 168. 7x = 28. x = 4.

Multiple choice
  1. 4.5 litres

  2. 4 litres

  3. 3.5 litres

  4. 3 litres

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let x be the amount of water added. CP = 28 * 8.5 = 238. SP = (28 + x) * 8.5. Profit = 12.5% of 238 = 29.75. SP = 238 + 29.75 = 267.75. (28 + x) * 8.5 = 267.75. 28 + x = 31.5. x = 3.5.

Multiple choice
  1. 20/57th part

  2. 37/57th part

  3. 37/20th part

  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the initial amount be 10 units (7 milk, 3 water). After replacing a fraction 'x' of the mixture with milk, the amount of water becomes 3 * (1 - x). We are given the new ratio 17:2, so the water part is 2/19 of the total. Thus, 3 * (1 - x) = 2/19 * 10, which simplifies to 1 - x = 20/57, so x = 37/57.