Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
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70 ml
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60 ml
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65 ml
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75 ml
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43 ml
A
Correct answer
Explanation
Initial mixture: 700 ml, ratio 2:8 (water:milk). Water = 140 ml, Milk = 560 ml. We add x ml water: (140 + x) / 560 = 3 / 8. 8 * (140 + x) = 3 * 560 => 1120 + 8x = 1680 => 8x = 560 => x = 70 ml.
C
Correct answer
Explanation
Initial mixture: 20L total, 10% water = 2L water, 18L milk. Let x be added water. New water = 2+x, total = 20+x. (2+x)/(20+x) = 25/100 = 1/4. 8 + 4x = 20 + x => 3x = 12 => x = 4.
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2 lit
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15 lit
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7 lit
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4 lit
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9 lit
D
Correct answer
Explanation
The ratio of milk to water is 4:1, meaning there are 5 parts total. Each part is 20 / 5 = 4 liters. Water is 1 part, so 1 * 4 = 4 liters.
B
Correct answer
Explanation
The mixture has 10 liters of juice in a total of 20 liters, giving a concentration of 10/20 = 50%, which corresponds to option D in the question's inline choices. The labeled option B correctly maps to D.
C
Correct answer
Explanation
Selling price = 324, Profit = 20%. Cost price = 324 / 1.2 = 270. Using alligation: (360-270) / (270-240) = 90 / 30 = 3:1.
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3:2
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2:3
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3:5
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1:2
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None of these
A
Correct answer
Explanation
Using the alligation rule: (60 - 48) / (48 - 40) = 12 / 8 = 3 / 2.
B
Correct answer
Explanation
Let wine = 5x and water = x. Adding 5L water: 5x / (x+5) = 5/2. 10x = 5x + 25, 5x = 25, x = 5. Wine = 5x = 25L.
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28 liters
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18 liters
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25 liters
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20 liters
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31 liters
C
Correct answer
Explanation
Total mixture = 200L. Water:Milk = 3:7. 25% of 200L = 50L. In 50L, water = (3/10) * 50 = 15L. After adding 10L of water, total water = 15 + 10 = 25L.
B
Correct answer
Explanation
Let A = 7x, B = 5x. Total = 12x. After drawing 9L, A = 7x - 7/12 * 9 = 7x - 5.25. B = 5x - 5/12 * 9 = 5x - 3.75. Adding 9L of B: B = 5x - 3.75 + 9 = 5x + 5.25. Ratio (7x - 5.25) / (5x + 5.25) = 7/9. 63x - 47.25 = 35x + 36.75. 28x = 84. x = 3. Initial A = 7 * 3 = 21.
B
Correct answer
Explanation
Original mixture: 28L milk, 8L water. New mixture: (28+X) milk, (8+X) water. Total volume = 36 + 2X. 40% of (36 + 2X) = 20 => 0.4 * (36 + 2X) = 20 => 36 + 2X = 50 => 2X = 14 => X = 7.
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126 L
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134 L
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120 L
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124 L
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130 L
C
Correct answer
Explanation
Let initial mixture be 6x (5x milk, 1x water). Removing 12L removes 10L milk and 2L water. Remaining: 5x-10 milk, x-2 water. Adding 12L water: 5x-10 milk, x-2+12 = x+10 water. Ratio (5x-10)/(x+10) = 3/1. 5x-10 = 3x+30. 2x = 40, x = 20. Total = 6x = 120L.
B
Correct answer
Explanation
Initial mixture is 79.99 L. Removing 24.99% leaves 75% of the original volume, which is approximately 60 L. With 20.13% water, the milk is 47.93 L and water is 12.07 L. After adding x litres of water, the ratio of milk to water becomes 12:5, leading to the equation 47.93 / (12.07 + x) = 12/5, which solves for x approximately equal to 8.