Quantitative Aptitude

Mensuration

2,507 Questions
All Direct Formula Application 1067 Shape Transformations 343 Mensuration Ratio Equations 277 Combined & Hollow Solids 247 Successive Percentage Changes 178 Inscribed & Circumscribed Figures 165 Cost Estimation Problems 100 Liquid Pour & Submergence 67 Unit Conversions 35 Path & Border Calculations 17 Time & Work Integration 7 Scale & Model Proportions 2

Mensuration Questions

Multiple choice

Directions: The following question consists of two quantities, Quantity I and Quantity II. You are to compare the two quantities and find the correct relationship between both the quantities. Quantity I: Area of a rectangle which is equal to the area of a square of side 22 cm Quantity II: Area of a rectangle whose perimeter is 80 cm and the ratio of length to width is 3 : 2

  1. Quantity I < Quantity II

  2. Quantity I > Quantity II

  3. Quantity I ≤ Quantity II

  4. Quantity I ≥ Quantity II

  5. Quantity I = Quantity II or no any relation
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Quantity I: Area = 22 * 22 = 484. Quantity II: Perimeter = 2(L+W) = 80, L+W = 40. L:W = 3:2, so L=24, W=16. Area = 24 * 16 = 384. 484 > 384.

Multiple choice

A solid is in the form of a cylinder with hemispherical ends. If the height of the solid is 26cm and diameter of cylindrical part is 14 cm, then find the cost of covering the solid with metal sheet (Cost of metal sheet is Rs.15/cm²).

  1. Rs.16570

  2. Rs.15440

  3. Rs.17160

  4. Rs.12420

  5. Rs.14370
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Cylinder height = 26 - 7 - 7 = 12 cm. Radius = 7 cm. Surface area = 2*pi*r*h (cylinder) + 4*pi*r^2 (two hemispheres) = 2*pi*7*12 + 4*pi*49 = 168*pi + 196*pi = 364*pi. 364 * 3.14159 * 15 = 17153. The closest option is 17160.

Multiple choice

Quantity I- 'Area of rectangle' Sum of circumference of circle and perimeter of rectangle is 220 cm and area of circle is 1386 sq. cm. If length of rectangle is more than radius of circle. Quantity II- 'Perimeter of square' Circumference of the circle is 132 cm and area of circle is 710 sq. cm more than area of square

  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or no relation
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

Directions: The question given below is followed by information given in statements I, II and III. You have to consider the information in all three statements and decide the information in which statement is not required to answer the question and therefore, can be dispensed with. What is the cost of a rectangular sheet? I. The length of the rectangle is 12 m and breadth is two third of its length. II. Perimeter of rectangle is 40 m. III. The cost of rectangular sheet of 200 m2 is Rs. 90.

  1. Only I

  2. Only II

  3. Only I and II

  4. Only I or II or III

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find the cost of the sheet, we need the area and the rate per square meter. Statement I gives dimensions (area), and Statement III gives the cost for a specific area. Statement II (perimeter) is redundant because area is already determined by length and breadth.

Multiple choice

Simmy has a sphere whose diameter is 70 cm. She wants to reduce its capacity by eight times. What should be its radius so that its capacity is reduced by eight times?

  1. 12.56 cm

  2. 16.8 cm

  3. 14.375 cm

  4. 17.5 cm

  5. 18.2 cm
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Volume of a sphere is (4/3) * pi * r^3. If capacity (volume) is reduced by 8 times, the radius must be reduced by the cube root of 8, which is 2. Original radius = 70 / 2 = 35 cm. New radius = 35 / 2 = 17.5 cm.