Reasoning
Logic and Fallacies
1,716 Questions
Understand the fundamentals of propositional logic, logical inference rules, and paradoxes. This set includes identifying logical fallacies, including those found in classical Nyaya logic. Strong grasp of these concepts is crucial for scoring well in the reasoning sections of competitive tests.
Propositional logic modelsLogical inference rulesTypes of logical fallaciesParadoxes and contingent truthsNyaya logic concepts
Logic and Fallacies Questions
Which of the following is a tautology?
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~(p ∨ q)
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(p ∧ q) → p
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p → (p ∨ q)
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~(p → q) → p
C
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "p → (p ∨ q)" is always true, because if "p" is true, then "p ∨ q" is also true, and if "p" is false, then "p → (p ∨ q)" is also true.
Which of the following is a contradiction?
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(p ∧ q) → p
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~(p ∨ q)
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p → (p ∨ q)
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~(p → q) → p
B
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p ∨ q)" is always false, because if "p" is true or "q" is true, then "p ∨ q" is true, and "~(p ∨ q)" is false.
Which of the following is a tautology?
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~(p ∧ q) → (~p ∨ ~q)
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(p ∨ q) → (~p → q)
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(p → q) → (~q → ~p)
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~(p → q) → (p ∧ ~q)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p ∧ q) → (~p ∨ ~q)" is always true, because if "p ∧ q" is false, then "~p ∨ ~q" is true, and if "p ∧ q" is true, then "~(p ∧ q)" is false.
Which of the following is a contradiction?
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(p ∨ q) → (~p → q)
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(p → q) → (~q → ~p)
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~(p → q) → (p ∧ ~q)
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~(p ∧ q) → (~p ∨ ~q)
C
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p → q) → (p ∧ ~q)" is always false, because if "p → q" is false, then "p ∧ ~q" is true, and if "p → q" is true, then "~(p → q)" is false.
Which of the following is a tautology?
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(p ∨ q) → (q ∨ p)
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(p ∧ q) → (q ∧ p)
-
~(p ∨ q) → (~p ∧ ~q)
-
~(p ∧ q) → (~p ∨ ~q)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "(p ∨ q) → (q ∨ p)" is always true, because if "p ∨ q" is true, then "q ∨ p" is also true, and if "p ∨ q" is false, then "(p ∨ q) → (q ∨ p)" is also true.
Which of the following is a contradiction?
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(p ∧ q) → (q ∧ p)
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~(p ∨ q) → (~p ∧ ~q)
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~(p ∧ q) → (~p ∨ ~q)
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(p ∨ q) → (q ∨ p)
C
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p ∧ q) → (~p ∨ ~q)" is always false, because if "p ∧ q" is false, then "~p ∨ ~q" is true, and if "p ∧ q" is true, then "~(p ∧ q)" is false.
Which of the following is a tautology?
-
~(p → q) → (p ∧ ~q)
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(p ∨ q) → (~p → q)
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(p → q) → (~q → ~p)
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~(p ∧ q) → (p → ~q)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p → q) → (p ∧ ~q)" is always true, because if "p → q" is false, then "p ∧ ~q" is true, and if "p → q" is true, then "~(p → q)" is false.
Which of the following is a contradiction?
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(p ∨ q) → (~p → q)
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(p → q) → (~q → ~p)
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~(p ∧ q) → (p → ~q)
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~(p → q) → (p ∧ ~q)
C
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "~(p ∧ q) → (p → ~q)" is always false, because if "p ∧ q" is false, then "p → ~q" is true, and if "p ∧ q" is true, then "~(p ∧ q)" is false.
Which of the following is a tautology?
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(p → q) → ((q → r) → (p → r))
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((p → q) ∧ (q → r)) → (p → r)
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((p → q) ∨ (q → r)) → (p → r)
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~(p → q) → (p ∧ ~q)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "(p → q) → ((q → r) → (p → r))" is always true, because if "p → q" is true, then "(q → r) → (p → r)" is also true, and if "p → q" is false, then "(p → q) → ((q → r) → (p → r))" is also true.
Which of the following is a contradiction?
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((p → q) ∧ (q → r)) → (p → r)
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((p → q) ∨ (q → r)) → (p → r)
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~(p → q) → (p ∧ ~q)
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(p → q) → ((q → r) → (p → r))
B
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p → q) ∨ (q → r)) → (p → r)" is always false, because if "p → q" is true and "q → r" is false, then "p → r" is false, and "((p → q) ∨ (q → r)) → (p → r)" is also false.
Which of the following is a tautology?
-
((p ∨ q) ∧ (p → r)) → (q → r)
-
((p ∧ q) ∨ (p → r)) → (q → r)
-
((p → q) ∧ (q → r)) → (p → r)
-
((p ∨ q) ∨ (p → r)) → (q → r)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p ∨ q) ∧ (p → r)) → (q → r)" is always true, because if "p ∨ q" is true and "p → r" is true, then "q → r" is also true, and if "p ∨ q" is false or "p → r" is false, then "((p ∨ q) ∧ (p → r)) → (q → r)" is also true.
Which of the following is a contradiction?
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((p ∧ q) ∨ (p → r)) → (q → r)
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((p → q) ∧ (q → r)) → (p → r)
-
((p ∨ q) ∨ (p → r)) → (q → r)
-
((p ∨ q) ∧ (p → r)) → (q → r)
A
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p ∧ q) ∨ (p → r)) → (q → r)" is always false, because if "p ∧ q" is true and "p → r" is false, then "q → r" is false, and "((p ∧ q) ∨ (p → r)) → (q → r)" is also false.
Which of the following is a tautology?
-
((p → q) ∧ (q → r)) → (p → r)
-
((p ∨ q) ∧ (p → r)) → (q → r)
-
((p ∧ q) ∨ (p → r)) → (q → r)
-
((p → q) ∨ (q → r)) → (p → r)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p → q) ∧ (q → r)) → (p → r)" is always true, because if "p → q" is true and "q → r" is true, then "p → r" is also true, and if "p → q" is false or "q → r" is false, then "((p → q) ∧ (q → r)) → (p → r)" is also true.
Which of the following is a contradiction?
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((p ∨ q) ∧ (p → r)) → (q → r)
-
((p → q) ∨ (q → r)) → (p → r)
-
((p ∧ q) ∨ (p → r)) → (q → r)
-
((p → q) ∧ (q → r)) → (p → r)
Correct answer
Explanation
A contradiction is a propositional formula that is always false, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p ∨ q) ∨ (p → r)) → (q → r)" is always false, because if "p ∨ q" is true and "p → r" is false, then "q → r" is false, and "((p ∨ q) ∨ (p → r)) → (q → r)" is also false.
Which of the following is a tautology?
-
((p → q) ∧ (q → r)) → (p → r)
-
((p ∨ q) ∧ (p → r)) → (q → r)
-
((p ∧ q) ∨ (p → r)) → (q → r)
-
((p → q) ∨ (q → r)) → (p → r)
A
Correct answer
Explanation
A tautology is a propositional formula that is always true, regardless of the truth values of its constituent propositions. In this case, the propositional formula "((p → q) ∧ (q → r)) → (p → r)" is always true, because if "p → q" is true and "q → r" is true, then "p → r" is also true, and if "p → q" is false or "q → r" is false, then "((p → q) ∧ (q → r)) → (p → r)" is also true.