Geometry Questions

Multiple choice
  1. 3

  2. 2

  3. 3/2

  4. 1

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The circle equation x^2 + y^2 - 2x - 6y + 6 = 0 has center (1, 3) and radius sqrt(1^2 + 3^2 - 6) = 2. A diameter of this circle is a chord of another circle with center (2, 1). The distance from (2, 1) to the line containing the diameter (which passes through (1, 3)) is needed. However, the diameter itself is a chord of the second circle, so the radius of the second circle R = sqrt(d^2 + r^2), where r=2 and d is the distance from (2, 1) to the center (1, 3). d = sqrt((2-1)^2 + (1-3)^2) = sqrt(1+4) = sqrt(5). R = sqrt(5 + 4) = 3.

Multiple choice
  1. $4.8$ $cm$
  2. $2.4$ $cm$
  3. $3$ $cm$
  4. $4$ $cm$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the center be O. Distance to AB is 2.7. Half of AB is 2.4. Radius is 2.5. Distance from center to AB is sqrt(2.5^2 - 2.4^2) = 0.7. Since chords are parallel and 2.7 apart, the distance from center to CD is 2.7 - 0.7 = 2.0. Half of CD = sqrt(2.5^2 - 2.0^2) = 1.5. CD = 3.0 cm.

Multiple choice
  1. $\left| a \right| <8$
  2. $\left| a \right| <4\sqrt { 2 } $
  3. $\left| a \right| <4$
  4. $\left| a \right| >4$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A chord making equal intercepts 'a' on axes means the line equation is x/a + y/a = 1, or x + y = a. The distance from the origin (0,0) to the line x + y - a = 0 must be less than the radius sqrt(8). Distance = |a| / sqrt(1^2 + 1^2) = |a| / sqrt(2). So, |a| / sqrt(2) < sqrt(8) implies |a| < sqrt(16) = 4.

Multiple choice
  1. $\dfrac{2}{3}$
  2. $\dfrac{2}{7}$
  3. $\dfrac{1}{8}$
  4. $\dfrac{3}{4}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Since AC is diameter, angle ABC = 90 degrees. In triangle ABC, BD=AB, so triangle ABD is isosceles. Using geometric properties of chords and segments in a circle, the segments satisfy power of a point or similar triangles. Given PC=2/5 and radius=1, the calculation leads to CD=2/3.

Multiple choice
  1. $11$
  2. $7$
  3. $9$
  4. $2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The common chord equation is (x^2+y^2+6x+4y+c) - (x^2+y^2+2x+2y) = 0, which is 4x + 2y + c = 0. For the quadrilateral to be a rhombus, the diagonals must bisect each other at 90 degrees. This condition leads to c = 11.

Multiple choice
  1. $2 x + y - 7 = 0$
  2. $x + 2 y + 1 = 0$
  3. $2 x - y - 13 = 0$
  4. $x - 2 y - 11 = 0$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The equation of a chord bisected at (x1, y1) is T = S1. T = x*x1 + y*y1 - 3(x+x1) + 4(y+y1). S1 = x1^2 + y1^2 - 6*x1 + 8*y1. Substituting (5, -3) gives 5x - 3y - 3(x+5) + 4(y-3) = 25 + 9 - 30 - 24. 2x + y - 27 = -20. 2x + y - 7 = 0.