Geometry Questions

Multiple choice
  1. 30 sq. cm

  2. 40 sq. cm

  3. 24 sq. cm

  4. 48 sq. cm

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The quadrilateral PQOR is composed of two congruent right-angled triangles, PQR and POR, where the radius OQ is 6 cm and the hypotenuse OP is 10 cm. Using the Pythagorean theorem, PQ = sqrt(10^2 - 6^2) = 8 cm. The area of one triangle is 1/2 * base * height = 1/2 * 6 * 8 = 24 sq. cm, so the total area is 24 * 2 = 48 sq. cm.

Multiple choice
  1. 2

  2. π 3

  3. 1 2

  4. 1

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For three circles of radii r1, r2, r3 touching each other and a common tangent, the relationship is 1/sqrt(r3) = 1/sqrt(r1) + 1/sqrt(r2). Here r1=4, r2=4. 1/sqrt(r3) = 1/2 + 1/2 = 1. So sqrt(r3) = 1, r3 = 1.

Multiple choice
  1. ( π 3 3 ) 1 2

  2. ( π 4 ) 1 2

  3. ( π 4 3 ) 1 2

  4. ( π 6 ) 1 2

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The sector has area (60/360)π = π/6. If OC = OD = x, triangle OCD has area (1/2)x^2 sin(60°) = sqrt(3)x^2/4. Equating this to half the sector area gives x = sqrt(π/(3sqrt(3))), corresponding to option A.