Geometry Questions

Multiple choice
  1. ${C}_{1}$ and ${C}_{2}$ are the same point and ${r}_{1}={r}_{2}$
  2. ${C}_{1}$ and ${C}_{2}$ are not necessarily the same point and ${r}_{1}={r}_{2}$.
  3. ${C}_{1}$ and ${C}_{2}$ are the same point and ${r}_{1}$ is not necessarily equal to ${r}_{2}$
  4. ${C}_{1}$ and ${C}_{2}$ are not necessarily the same point and ${r}_{1}$ is not necessarily equal to ${r}_{2}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice
  1. $\dfrac{r_1r_2}{\left(\sqrt{r_1}+\sqrt{r_2}\right)^2}$
  2. $\sqrt{r_1r_2}$
  3. $\dfrac{r_1+r_2}{2}$
  4. $\dfrac{r_1-r_2}{2}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For two circles of radii r1 and r2 touching externally, the radius r of a third circle touching both and their common tangent is given by 1/sqrt(r) = 1/sqrt(r1) + 1/sqrt(r2). Solving for r gives r = r1*r2 / (sqrt(r1) + sqrt(r2))^2.

Multiple choice
  1. $(0,-6)$
  2. $(1,-5)$
  3. $(0,-9)$
  4. none

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The circle x^2 + y^2 = 4 has center (0,0) and radius 2. A circle tangent to it at (2,0) must have its center on the x-axis. Since it also passes through (6,0), the center must be the midpoint of the chord or satisfy the distance condition. Any circle tangent at (2,0) must have a center at (c, 0). The distance from (c,0) to (2,0) is |2-c| = radius. The distance from (c,0) to (6,0) is |6-c| = radius. Thus |2-c| = |6-c|, which has no solution (2-c = 6-c implies 2=6).

Multiple choice
  1. $6$
  2. $3$
  3. $2$
  4. $1$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The center of similitude is given as (0, 2.5). The circles have centers C1(-3, 1) and C2(1, 3) with radii r1=3 and r2=2. The length of the common tangent through the center of similitude can be calculated using the power of the point formula, which is sqrt(S1) or sqrt(S2).

Multiple choice
  1. $\theta = 2 \cos^{-1} \displaystyle \left ( \frac{a-b}{a+b}\right )$
  2. $\theta = 2\tan^{-1} \displaystyle \left ( \frac{a+b}{a-b}\right )$
  3. $\theta = 2\sin^{-1} \displaystyle \left ( \frac{a+b}{a-b}\right )$
  4. $\theta = 2 \sin^{-1} \displaystyle \left ( \frac{a-b}{a+b}\right )$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For two circles of radii a and b touching externally, the angle theta between the direct common tangents is given by the formula sin(theta/2) = (a-b)/(a+b). Thus, theta = 2 * arcsin((a-b)/(a+b)).

Multiple choice
  1. $ x -\sqrt{3}y + 2 = 0$
  2. $ \sqrt{3} x -y + 2 = 0$
  3. $\sqrt {3}x -y -2 = 0$
  4. $ x +\sqrt {3} y + 2 = 0$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

C1 is centered at (0,0) with radius 1. C3 has center (0.5, sqrt(0.75)) = (0.5, sqrt(3)/2) and radius 1. The common tangent not passing through C2 is the line tangent to both C1 and C3, which is sqrt(3)x - y + 2 = 0.

Multiple choice
  1. 3

  2. 13

  3. 25

  4. 35

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The family of circles passing through A and B is S + kL = 0. The common chord of any member and the fixed circle is the radical axis. The radical axis of the family and the fixed circle passes through the intersection of the fixed circle and the line AB. Solving for the fixed point yields the result.