Biology

Genetics and Plant Breeding

1,177 Questions

Genetics and Plant Breeding explores the principles of heredity, chromosomal inheritance, and hybridization techniques. It includes key concepts like Mendelian genetics, gene linkage, and polygenic inheritance. This topic is essential for students tackling advanced biology or botany sections in competitive examinations.

Mendelian InheritanceChromosome TheoryGene LinkagePolygenic InheritancePlant HybridizationPopulation Genetics Equilibrium

Genetics and Plant Breeding Questions

Multiple choice
  1. Only a

  2. Only a and b

  3. Only b

  4. Only b and c

  5. Only c

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

This is the correct option as this statement is false. Blonde hair is a phenotype produced by the genotype hh.

Multiple choice
  1. a - 2, b - 1, c - 3

  2. a - 2, b - 3, c - 1

  3. a - 1, b - 3, c - 2

  4. a - 1, b - 2, c - 3

  5. a - 3, b - 1, c - 2

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

This is the correct option. Gene is a unit of heridity that transfers characteristics from parents to their offsprings during reproduction. Genotype is the description of genes present in an organism. Phenotype is the trait that is visible in an organism.

Multiple choice
  1. P and S

  2. P, Q and R

  3. Q, R and S

  4. P, Q, R and S

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In X-linked recessive inheritance, males are primarily affected because they have only one X chromosome. Affected females require an affected father and a carrier or affected mother to inherit two recessive alleles. Sons of affected females always receive the X chromosome with the recessive allele and will be affected. These traits can skip generations through carrier females, so S is false.

Multiple choice
  1. P - 1/4 and Q - 52.6%

  2. P - 3/4 and Q - 26.3%

  3. P - 3/4 and Q - 50%

  4. P - 81/256 and Q - 26.3%

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For a heterozygous female (X^H X^h) crossed with a normal male (X^H Y): each child has 1/4 chance of being unaffected (X^H X^H female or X^H Y male). So P (unaffected) = 3/4. For 5 offspring, the probability exactly 2 are affected is calculated using binomial distribution: C(5,2) × (1/4)^2 × (3/4)^3 = 10 × 1/16 × 27/64 ≈ 26.3%.

Multiple choice
  1. Every affected person should have at least one affected parent.

  2. Males and females should be equally often affected.

  3. An affected person has a 50% chance of transmitting the dominant allele to each offspring.

  4. All the daughters of an affected male will be affected but none of the sons.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For autosomal dominant traits, every affected individual must have an affected parent (except new mutations), males and females are equally affected, and there's a 50% transmission risk to each offspring. However, both sons AND daughters of an affected male have equal 50% chance - not all daughters and no sons. This sex-specific pattern describes X-linked inheritance, not autosomal dominant.

Multiple choice
  1. The sum of any set of allele frequencies is always 1.

  2. If there are two alleles at a locus and we know the frequency of one of them, we can obtain the frequency of the other by subtraction.

  3. If an allele is missing from a population, its frequency is 0.

  4. If two populations have the same allele frequencies at a locus, they must have the same proportion of homozygotes at that locus.

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Allele frequencies always sum to 1, and if there are two alleles, knowing one frequency gives the other. A missing allele has frequency 0. However, two populations can have identical allele frequencies but different homozygote proportions because the frequencies themselves don't determine homozygosity - you need to know whether the population is in Hardy-Weinberg equilibrium to make that calculation.

Multiple choice
  1. P and Q

  2. P and S

  3. Q and R

  4. R and S

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Classical Mendelian traits are qualitative and show discontinuous variation (distinct categories like tall vs short). They are typically monogenic (controlled by one or few genes), not polygenic. Polygenic traits show continuous variation and are called quantitative or metric traits, not qualitative.

Multiple choice
  1. P – 0%, Q – 0%, R – 38%, S – 45%

  2. P – 25%, Q – 50%, R – 45%, S – 38%

  3. P – 0%, Q – 25%, R – 45%, S – 38%

  4. P – 25%, Q – 0%, R – 38%, S – 45%

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For test cross of AaBb: P (unlinked) - parental aabb is 1/4 (25%). Q (completely linked) - aabb requires no crossover, so 50% parental types. R (10 map units) - 10% recombinants, so aabb = 45% parental. S (24 map units) - 24% recombinants, so aabb = 38% parental. The further apart the genes, the more crossing over, so fewer parental aabb progeny.

Multiple choice
  1. 60 Aabb, 440 aaBb, 440 AaBb and 60 aabb

  2. 0 Aabb, 0 aaBb, 440 AaBb and 440 aabb

  3. 440 Aabb, 440 aaBb, 60 AaBb and 60 aabb

  4. 60 Aabb, 60 aaBb, 440 AaBb and 440 aabb

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The genes are 12 map units apart, so the recombination frequency is 12%. Parental gametes (AB and ab) occur 88% of the time (44% each), while recombinant gametes (Ab and aB) occur 12% of the time (6% each). When AaBb is crossed with aabb, we get 440 AaBb, 440 aabb, 60 Aabb, and 60 aaBb.

Multiple choice
  1. The locus that determines cherub wings

  2. The locus that determines cinnabar eyes

  3. The locus that determines black body

  4. Cannot be determined

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In a three-point cross, the double crossover classes have the lowest frequency. Here, ch b+ cn+ (60) and ch+ b cn+ (111) are the double crossovers. Comparing these to the parental types (ch+ b+ cn+ at 780 and ch b cn at 769), we see that cn+ stays with ch+ (parental) and with ch (double crossover), meaning cn is in the middle. The gene order is ch-cn-b.

Multiple choice
  1. Mitochondrial Adam

  2. Nucleic Adam

  3. X-chromosomal Adam

  4. Y-chromosomal Adam

  5. Somaclonal Adam

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

In human genetics, Y-chromosomal Adam (Y-MRCA) is a hypothetical name given to the most recent common ancestor (MRCA) from whom all currently living people are descended patrilineally.